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elena-s [515]
2 years ago
12

Distributive Property to solve the equation. 5(x - 6) + 8 = 7x- 8 (Type the value of x.) ​

Mathematics
2 answers:
Zarrin [17]2 years ago
8 0
X = -7, have a good day !
vivado [14]2 years ago
6 0

Answer:

x=−7

Solving for X:

Step 1: Simplify both sides of your equation.

5x−22=7x−8

Step 2: Subtract 7x from both sides.

5x−22−7x=7x−8−7x

−2x−22=−8

Step 3: Add 22 to both sides.

−2x−22+22=−8+22

−2x=14

Step 4: Divide both sides by -2.

-2x/-2 = 14/-2

^ x = -7

THEREFORE:

x is −7

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Amanda, Boris, and Jose sent a total of 124 text messages during the weekend. Amanda sent 8 fewer messages than Jose
GrogVix [38]

Answer:

Amanda= 14

Boris = 88

Jose= 22

Step-by-step explanation:

Amanda= jose-8

Boris = 4×jose

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total all = 124

(jose-8)+(jose×4)+(jose)= 124

so we substitute jose with X .

(X-8)+(4X)+(X)=124

6X-8= 124.

6X=124+8

X=132/6

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Volume & surface! May I please have help
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Answer:

D

Step-by-step explanation:

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=(area of base)×2 + (area of curved surface)

=(\frac{20}{2} )^{2} \pi× 2 + 20\pi × 25

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2 years ago
Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?
Bond [772]

Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

  • y=-\frac{1}{5}x+\frac{13}{5}

Step-by-step explanation:

Given the equation

5x - y = 12

converting the line into the slope-intercept form y = mx+b, where m is the slope

-y = 12-5x

y = 5x-12

The slope of the line = m = 5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope of the line and (x₁, y₁) is the point

substituting the slope of new line = -1/5 and (-2, 3)

y-y_1=m\left(x-x_1\right)

y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)

y-3=-\frac{1}{5}\left(x+2\right)

Add 3 to both sides

y-3+3=-\frac{1}{5}\left(x+2\right)+3

y=-\frac{1}{5}x+\frac{13}{5}

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

  • y=-\frac{1}{5}x+\frac{13}{5}
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3 years ago
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