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Olegator [25]
3 years ago
11

2y - 6 = -6x, solve for y (must be in form y = mx + b)

Mathematics
1 answer:
nalin [4]3 years ago
7 0

Answer:

y=-3x+3

Step-by-step explanation:

hope this helps :)

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100 POINTS??? HELP ME ASAP
Katarina [22]

Answer:

35

Step-by-step explanation:

Double the first equation and get 2x + 2y = 300 (1). Call the second equation 2x + 5y = 405 (2). Calculate (2) - (1) to get 3y = 105, so y = 35.

5 0
3 years ago
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At M & P’s Deli, two pastrami sandwiches and five sodas cost $12.65, while three pastrami sandwiches and two sodas also cost
Olegator [25]

Answer:

37.95

Step-by-step explanation:

MATH

8 0
2 years ago
$500 shared in ratio 2:3:9
RideAnS [48]
2:3:9......added together = 14

2/14 (500) = 1000/14 = 71.43
3/14 (500) = 1500/14 = 107.14
9/14 (500) = 4500/14 = 321.43
6 0
3 years ago
What is 0.19 as a fracton
Lorico [155]

Answer:

u can make it a fraction

Step-by-step explanation:

6 0
3 years ago
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Consider sampling heights from the population of all female college soccer players in the United States. Assume the mean height
Verizon [17]

Answer:

The approximated value of the standard deviation is 0.35.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>n</em> = 100

<em>σ</em> = 3.5

<em>μ</em> = 66

As the sample size is quite large, i.e. <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.

Then the approximated value of the standard deviation of sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{3.5}{\sqrt{100}}\\\\=0.35

Thus, the approximated value of the standard deviation is 0.35.

5 0
4 years ago
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