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2 years ago

Please help me, picture below.

Mathematics

1 answer:

Lesechka [4]2 years ago

8 0

The answer is the last one, 8 square root 6 because when factoring out 486 you will get 9 square root 6. When factoring out 24, you will get 2 square root 6 and the 6 is already factored out. After that you add and subtract and you will get the last answer 8 square root 6. Hope that helped.

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find the product with the exponent in the simplest form. Then, identify the values of x and y. 6^1/3 * 6^1/4 = 6^x/y

mr Goodwill [35]

<span>6^1/3 * 6^1/4 = 6^x/y

The key to solving this problem is understanding properties of exponents:
If you are multiplying two powers with the same base (in this case the base is 6), the result is the base raised to the power of the two exponents added together.

6^1/3+1/4 = 6^x/y
6^7/12 = 6^x/y

So the product would be 6^7/12
x = 7
y = 12</span>

6 0

2 years ago

In a football tournament, the Bees scored 9 less than three times as many points as the Hornets. The Wasps scored 28 more points

Elina [12.6K]

Given:

Bees scored 9 less than three times as many points as the Hornets.

Wasps scored 28 more points than the Hornets.

Together the three teams scored 184 points.

To find:

The required equation for this scenario.

Step-by-step explanation:

Let x represent the number of points scored by the Hornets.

Bees scored 9 less than three times as many points as the Hornets.

Bees score = 3x-9

Wasps scored 28 more points than the Hornets.

Wasps score = x+28

Together the three teams scored 184 points.

$(3x-9)+x+(x+28)=184$

Therefore, the required equation is $(3x-9)+x+(x+28)=184$ .

3 0

3 years ago

Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1

taurus [48]

$\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.$

5 0

3 years ago

If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se

notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 5$

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{110 - 100}{5}$

$Z = 2$

$Z = 2$ has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0

2 years ago

6 (r - 4) + r + 30 - 7r

GrogVix [38]

6r-24+r+30-7r (the we divide the regular numbers on one side and the others on the other side)Like this:
(6r+r-7r)+(-24+30)
(7r-7r)+6
And the final answer is 6

8 0

3 years ago