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scoundrel [369]
2 years ago
7

Find the equation that represent the proportional relationship in this graph for you and terms of x​

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0

y =  \frac{1}{6} x \\

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if the xy-plane, the graph of y=x^2 and the circle with center (0,1) and radious 3 have how many points of intersection?
Rashid [163]
\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
radius={{ r}}\\
----------\\
center\ (0,1)\to 
\begin{cases}
h=0\\
k=1
\end{cases}\\
r=3
\end{cases} 
\\\\\\
(x-0)^2+(y-1)^2=3^2\implies x^2+(y-1)^2=9
\\\\\\
(y-1)^2=9-x^2\implies y=\sqrt{9-x^2}+1\\\\
-----------------------------\\\\
\textit{where do the parabola and circle intersect? set them to equal}
\\\\\\



\bf \begin{cases}
y=x^2\\\\
y=\sqrt{9-x^2}+1
\end{cases}\qquad y=y\implies  x^2=\sqrt{9-x^2}+1

solve for "x"
6 0
3 years ago
The cashier at Alexanders Market put 2 boxes of cereal, 2 jars of peanut butter, 3 cans of tuna fish and 5 cans of cat food into
Andrei [34K]

Answer:

23 1/2

Step-by-step explanation:

8 0
3 years ago
4) 3+i,<br> 1-i<br> All additional zeroes
In-s [12.5K]

Answer: 4+2i is the answer i think

Step-by-step explanation:

7 0
2 years ago
Blank divided by blank equals 6 what is the two blanks
Travka [436]
36 by 6 blah blah blah
4 0
2 years ago
Read 2 more answers
) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection
RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

C_{(m,n)} = \frac{m!}{n!(m-n)!}

In this question, m = 18, n = 9. So the total number of possibilities is:

T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715

The probability is the number of desired possibilities divided by the number of total possibilities. So

P = \frac{715}{48620} = 0.015 = 1.5%

The probability the he or she will answer correctly is 1.5%

3 0
3 years ago
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