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scoundrel [369]
3 years ago
7

Find the equation that represent the proportional relationship in this graph for you and terms of x​

Mathematics
1 answer:
mr_godi [17]3 years ago
7 0

y =  \frac{1}{6} x \\

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3x(x2 + 2x – 6) + 4(x2<br> – 6x + 2)
Drupady [299]

Step-by-step explanation:

3x(x2 + 2x – 6) + 4(x2

– 6x + 2)

4 0
2 years ago
You have 63 coins in your piggy bank, all quarters and nickels. The total amount is $12.55. How many quarters do you have?
Kaylis [27]

Answer:

47

Step-by-step explanation:

divide 1200 by 25 and u get 47 so we have 1 nickel to add the 5 cents.

4 0
2 years ago
Chaim tried to prove that AUTS ~ AUDE in the following figure, but his proof is wrong.
omeli [17]

Answer:

it’s A it is not given the ST and DE are parallel

Step-by-step explanation:

7 0
3 years ago
A worker is to construct an open rectangular box with a square base and a volume of 196196 ft cubedft3. If material for the bott
Archy [21]

Answer:

Therefore the dimensions of the box is 7 ft by 7 ft by 4 ft.

Therefore the minimum cost to manufacture the box is $12936.

Step-by-step explanation:

Given the volume of the open box is 196 cube ft.

Let the one side of the base of the box be x.

Since the base of the box is square in shape.

The other side of the base is also x.

The area of the base of the box = x² square ft

Let the height of the box be h.

The volume of the box is = Area of the base× height

                                          =(x²×h) cube ft.

                                           =x²h cube ft.

According to the problem,

x²h=196

\Rightarrow h=\frac{196}{x^2}

The material cost for the bottom is $88 per square ft and the material cost for the sides $77  per square ft.

The material cost for the bottom of the box = $(88×x²)

                                                                         =$88x²

The area sides = 2(length+width)height

                       =2(x+x)h

                      =4xh square ft.

The material cost for the sides of the box =$(77×4xh)

                                                                    =$308 xh

Total cost to make the box is =$(88x²+308 xh)

∴C=88x²+308 xh    [ C is in dollar]

Now putting h=\frac{196}{x^2}

C=88x^2+308x\times \frac{196}{x^2}

\Rightarrow C=88x^2+ \frac{60368}{x}

Differentiating with respect to x

C'=176x- \frac{60368}{x^2}

Again differentiating with respect to x

C''=176+ \frac{120736}{x^3}

Now to find the minimum cost, we set C'=0

\therefore 176x- \frac{60368}{x^2}=0

\Rightarrow 176x= \frac{60368}{x^2}

\Rightarrow x^3= \frac{60368}{176}

\Rightarrow x^3=343

\Rightarrow x=7

Now, C''|_{x=7}=176+ \frac{120736}{7^3}>0

Therefore at x=7, the manufacturing cost will be minimum.

The height of the box is h=\frac{196}{7^2} = 4ft

Therefore the dimensions of the box is 7 ft by 7 ft by 4 ft.

The manufacturing cost is C=88.7^2+ \frac{60368}{7}   [ putting x=7]

                                             =$12936

Therefore the minimum cost to manufacture the box is $12936.

4 0
3 years ago
How many solutions does the following system have 3x+2y=1 -9x-6y=3
Sladkaya [172]
Since there are 2 variables there will be 2 answers.
7 0
3 years ago
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