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Genrish500 [490]
2 years ago
14

FOR ALL YOU STAR WARS FANS OUT THERE MY TEACHER GAVE US A STAR WARS MATH QUESTION. CHECK MY ANSWER MYBE? He asked how fast a bla

ster bolt fom a Star Destroyer fires. So i used the first scene in Star Wars 4 A New Hope.
A rebel blockade runner is approx 150 meters long...
to find how far it i from the Star Destroyer... i need perspective and camera angle
I am just going to go with a distance of 10 +/- 3 Blockade lengths. In meters, maybe I could say 1,500 +/- 500 meters (which is a different estimate). That seems pretty far, but oh well. If I use the distance above, I can say the bolt speed is about 1.807 x 105 m/s with an uncertainty of about +/- 6,000 m/s. Here I assumed the uncertainty in the time was sufficiently small to be ignored (compared to the uncertainty in the distance).
SOOOOOO. A Star wars blaster fires a bolt at approx 6k meters per second. ACCURATE?
Mathematics
1 answer:
kvv77 [185]2 years ago
3 0
(Links in comments below)

I'm using the clip from link [1] as a reference, i.e. the shot of the Tantive IV escaping the Devastator towards the camera, which lasts approximately 5 seconds (2:27 - 2:32). I recorded the particular shot, then carried out a cursory frame-by-frame analysis. The shot itself consists of 371 frames.

At around frame 15 - about 0.233s into the clip - one can barely make out a green projectile being launched from one of the Devastator's batteries. It takes the projectile between 19 and 20 frames (I'll round up to 20) - now at frame 35, about 0.333s later - for it to reach the left edge of the camera's field of view.

Let's suppose the Tantive IV was situated in roughly the same physical position in frame 1 as the projectile was in frame 35.

Now, the Tantive IV exits the screen at around frame 182 - about 3.017s into the clip. According to link [2], the standard CR90 "Corellian" Corvette can reach speeds of up to 950km/h. The Rebels are fleeing the Empire, so it's reasonable to assume that they are moving as fast as they can. Let's also assume they're traveling at a constant rate, and that the tractor beam aboard the Devastator hasn't been activated yet.

Note: Link [2] refers to this maximum speed as "atmosphere speed". I can't find any references as to what this means, so I assume it means something along the lines of "same conditions as Earth's atmosphere". The two ships are flying above Tatooine, which is inhabited in part by humans, so it's probably a safe bet that the atmospheres of Tatooine and Earth aren't that dissimilar.

So if it takes the Tantive IV about 3.017s to move (approximately) the same distance as the Devastator's projectile, and if we assume the Tantive IV is moving at maximum speed, then it must have traveled a distance d of (approximately)

d=\dfrac{950\text{ km}}{1\text{ h}}\times(3.017\text{ s})\implies d\approx0.796\text{ km}

However, it's quite clear from the previous shot that the assumption above is not all that accurate. So let's consider "your" assumption, that the distance between the Tantive IV and the Devastator is about 10 times its own length, i.e. d\approx2.296\text{ km}. Now, if the projectile takes about 0.333s to travel the same distance, then it must have moving at a speed r of (approximately)

2.296\text{ km}=r\times(0.333\text{ s})\implies r\approx24,821.6\dfrac{\text{km}}{\text{h}}
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Complete Question

A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.

Answer:

The  value  of the 16th percentile  is  x = 20

The range for the middle 3 standard deviation is  10 \to 40

Step-by-step explanation:

From the question we are told that

     The  mean is  \mu  =  25

     The  median is  m  =  24

     The  mode is  n =  26

     The  standard deviation is  \sigma  =  5

Generally the 16th percentile is mathematically represented as

  P(x)= P(\frac{X  -  \mu }{ \sigma }   \le \frac{x- 25 }{5} ) = 0.16[/teGenerally  [tex]\frac{X -  \mu}{\sigma }  =  Z(The  \  standardized \  value \ of  \ X  )

So

       P(x) =  P(Z \le \frac{ x -  25}{5} ) =  0.16

Now from the normal distribution table  the z-score of  0.16 is  

      z =  -1

       P(x) =  P(Z \le \frac{ x -  25}{5} ) =  P(Z \le -1 )

=>  \frac{x- 25}{5}  =  -1

=>    x- 25  =  -5

=>      x =  25-5

=>       x = 20

The range for the middle 3 standard deviation is mathematically represented

        \mu  -  3\sigma \to \mu + 3\sigma

        25 -  3(5 ) \to 25 +  3(5 )

         10 \to 40

 

   

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