What is another fraction for 3/10

How do you solve log base 64 of 0.5 = x?

alexandr1967 [171]

㏒₆₄(0.5) = x
  64ˣ = 0.5
  ㏑(64ˣ) = ㏑(0.5)
x㏑(64) = ㏑(0.5)
  x㏑(2⁶) = ㏑(2⁻¹)
6x㏑(2) = -㏑(2)
6㏑(2) 6㏑(2)
x = ⁻¹/₆

4 0

3 years ago

An air plane moves at a constant speed of 120 miles per hour for 3 hours. How far does it go?

Anvisha [2.4K]

Answer: 360

Step-by-step explanation: All you got to do is multiply 120 by 3

7 0

3 years ago

Read 2 more answers

Can someone help me out with some pesky math quiz :) I put a pic

Sindrei [870]

1. Simplifying ∛54 gives 3∛2

2. 27^1/3 * (27)^3 is equal to 27

3. The expression (2j4k)^4/5 can be written as $\sqrt[4]{32j^{20}k^{5} }^{5}$ making the first option the correct option

4. simplifying $\sqrt[4]{16x^{4} y^{12} }$ will result to 2x∛y

5. simplifying $\sqrt[5]{2940x^{13} y^{7} }$ will result to $14x^{6} y^{3} \sqrt{15xy}$ making the last option the correct option

<h3>How to simplify $\sqrt[5]{2940x^{13} y^{7} }$ </h3>

given data

$\sqrt[5]{2940x^{13} y^{7} }$

= ( 2940 * x^13 * y^7 )^1/5

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{1/5*5/2}$

$= ( 2^2 * 5 * 3 * 7^2 * x^{12} * x * y^6 * y )^{5/5*1/2}$

multiplying the values inside the parenthesis by ^1/2

$= ( 2 * 5^{1/2} * 3^{1/2} * 7 * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14* 5^{1/2} * 3^{1/2} * x^{6} * x^{1/2} * y^3 * y^{1/2} )$

$= ( 14 * x^6 * y^3 ) ( 5^{1/2} * 3^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15^{1/2} * x^{1/2} * y^{1/2} )$

$= ( 14x^6y^3 ) ( 15xy)^{1/2}$

$= ( 14x^6y^3 ) \sqrt{( 15xy)}$

we can therefore say that the last option is the answer

Read more on equations here: brainly.com/question/22688504

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3 0

1 year ago

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.

EleoNora [17]

Answer:

The system of equation are $\left \{ {{15+1x} \atop {3+5x}} \right.$ .

In 3 weeks, the friends will each have passed 18 scales.

Step-by-step explanation:

Let number of weeks be 'x'.

Given:

Number of scale Pablo has passed = 15 scales

Number of scale Kayla has passed = 3 scales

Number of scales passing per week by Pablo = 1 scale

Number of scales passing per week by Kayla = 5 scale

We need find the number of weeks when both have same scales.

First we will find the Total number of scales Pablo will passed after 'x' weeks.

Total number of scales Pablo will passed after 'x' weeks is equal to sum of Number of scale Pablo has passed and Number of scales passing per week by Pablo multiplied by number of weeks.

framing in equation form we get;

Total number of scales Pablo will passed after 'x' weeks = $15+1x$

Now we will find Total number of scales Kayla will passed after 'x' weeks.

Total number of scales Kayla will passed after 'x' weeks is equal to sum of Number of scale Kayla has passed and Number of scales passing per week by Kayla multiplied by number of weeks.

framing in equation form we get;

Total number of scales Kayla will passed after 'x' weeks = $3+5x$

Hence the system of equation are $\left \{ {{15+1x} \atop {3+5x}} \right.$ .

Now we need to find the number of weeks when both have passed equal scales.

Hence we can say that;

Total number of scales Pablo will passed after 'x' weeks = Total number of scales Kayla will passed after 'x' weeks

Substituting the value we get;

$15+1x=3+5x$

On Solving the equation we get;

Combining like terms first;

$5x-x=15-3\\\\4x=12$

Now by Division property dividing both side by 4 we get;

$\frac{4x}{4}=\frac{12}{4} \\\\x=3 \ weeks$

Now we will find the total scales passed by each after 3 weeks;

Total number of scales Pablo will passed after 3 weeks = $15+x=15+3 = 18 \ scales$

Total number of scales Kayla will passed after 3 weeks = $3+5x=3+5\times3 = 18 \ scales$

Hence: In 3 weeks, the friends will each have passed 18 scales.

4 0

3 years ago

A professional baseball player hits a homerun on a .75kg baseball. The ball accelerated at a rate of 1200m/s2. How much force di

brilliants [131]

Answer:

The force the player hit the ball with is 900 N

Step-by-step explanation:

Given;

mass of the baseball, m = 0.75 kg

acceleration of the ball, a = 1200 m/s²

The force the player hit the ball with is given by the following equations;

F = ma (based on Newton's second law of motion)

where;

F is the applied force

m is mass of the baseball

a is the acceleration of the baseball

F = ma

F = (0.75 x 1200)

F = 900 N

Therefore, the force the player hit the ball with is 900 N

3 0

3 years ago