Ask question

Ask question

All categories

3 years ago

9

Chayse is working on analyzing the electromagnetic spectrum, focusing on ultraviolet rays. He determines that a UV ray has a fre

quency of 1.53 × 1016 Hz and a wavelength of 1.96 × 10-8 m. Are his results reasonable? Explain your answer.

2 answers:

m_a_m_a [10]3 years ago

8 0

Explanation :

Frequency of the UV rays, $\nu=1.53\times 10^{16}\ Hz$

Wavelength of UV rays, $\lambda=1.96\times 10^{-8}\ m$

We know that the speed of UV rays is same as that of speed of light.

Also, $c=\nu\times \lambda$

c is the speed of light

$c=1.53\times 10^{16}\ Hz\times 1.96\times 10^{-8}\ m$

$c=299880000\ m/s$

It is approximately equal to the speed of light ( $3\times 10^8\ m/s$ ). The product of wavelength and the frequency equals the speed of light. So, his results is reasonable.

Valentin [98]3 years ago

6 0

Yes, Chayse's results are reasonable because all parts of the electromagnetic spectrum travel at the speed of light. By multiplying his results for frequency and wavelength, I can see that the velocity of the UV ray is close to the speed of light.

You might be interested in

Provide an example of a technological advancement that has had a positive effect on the environment

Dennis_Churaev [7]

Genetically engineering endangered keystone species that are vital to the environment to be more resilient against harmful predators and/or toxins, pathogens, etc.

8 0

3 years ago

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 15.6

VladimirAG [237]

To solve this problem it is necessary to take into account the kinematic equations of motion and the change that exists in the volume flow.

By definition the change in speed is given by

$v_f^2-v_i^2 = 2ax$

Where,

x= distance

$v_f =$ final velocity

$v_i =$ initial velocity

a = acceleration

On the other hand we know that the flow of a fluid is given by

$\dot{V} = Av$

Where,

A = Area

v = Velocity

PART A )

Applying this equation to the previously given values we have to

$v_f^2-v_i^2 = 2ax$

$v_f^2-0 = 2*(9.8)(15.6)$

$v_f^2=305.76$

$v_f = 17.48$

Therefore the velocity of the water leaving the hole is 17.48m/s

PART B )

In the case of the hole we take the area of a circle, therefore replacing in the flow equation we have to,

$\dot{V} = \pi r^2 v$

$r = \sqrt{\frac{\dot{V}}{\pi v}}$

$r = \sqrt{\frac{3*10^{-3}*\frac{1}{60}}{\pi (17.48)}$

$r = \sqrt{9.10*10^{-7}}$

$r = 0.54*10^{-4}$

The diameter is 2 times the radius, then is $1.91*10^{-3}$ m or 1.91mm

<em>Note: The rate flow was converted from minutes to seconds.</em>

8 0

3 years ago

The scatter plot above shows the relationship between the pressure and volume of a gas (at fixed temperature). Which of the foll

Aleonysh [2.5K]

I think the correct answer from the choices listed above is option C. The scatter plot above shows the relationship between the pressure and volume of a gas in which the <span>pressure of a gas increases as its volume decreases. However, they are not linearly related. Hope this answers the question.</span>

8 0

4 years ago

1. What is the efficiency of a heat engine that does 1250 J of work and gives off 5250 J of heat to

vladimir2022 [97]

answer: in pic

explanation: found it here http://gaaq.weebly.com/uploads/7/8/8/4/78844490/chapter_11_q_as.pdf

7 0

3 years ago

Read 2 more answers

If a 2kg ball has and initial velocity of

lakkis [162]

Answer:

$\boxed {\boxed {\sf 12 \ Newtons }}$

Explanation:

Force is equal to the product of mass and acceleration.

$F=m*a$

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

$a=\frac{V_f-V_i}{t}$

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

$V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s$

Substitute the values into the formula.

$a=\frac{10 \ m/s-4 \ m/s }{1 \ s}$

Solve the numerator.

$a=\frac{6 \ m/s}{1 \ s }$

Divide.

$a= 6 \ m/s/s=6 \ m/s^2$

2. Calculate Force

Now we know the acceleration and the mass.

$m= 2 \ kg \\a= 6 \ m/s^2$

Substitute the values into the fore formula.

$F= 2 \ kg * 6 \ m/s^2$

Multiply.

$F= 12 \ kg*m/s^2$

1 kilogram meter per square second is equal to 1 Newton.
Our answer of 12 kg*m/s² is equal to 12 Newtons

$F= 12 \ N$

The force applies to the ball was <u>12 Newtons.</u>

8 0

3 years ago