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3 years ago

8

Provide an example of a technological advancement that has had a positive effect on the environment

1 answer:

Dennis_Churaev [7]3 years ago

8 0

Genetically engineering endangered keystone species that are vital to the environment to be more resilient against harmful predators and/or toxins, pathogens, etc.

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Look at the picture below. The boy is swinging back and forth on the swing. At which point is the potential energy of a swing th

Ilia_Sergeevich [38]

The potential energy of a swing is greatest at the top of the swing. (Point A).

5 0

3 years ago

Read 2 more answers

A point charge Q is placed at the center of a conducting spherical shell (inner radius a, outer radius b). What is the electric

sp2606 [1]

Answer:

a) $E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

b)E=0

c) $E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

Explanation:

Given that

A point charge Q is placed at the center of a conducting spherical shell .Due to this - Q charge will induce on the inner sphere surface and +Q will induce on the outer sphere surface .

a) r < a

At a radius r ,from gauss theorem

$E.ds=\dfrac{q_i}{\varepsilon _o}$

$E\times 4\pi r^2=\dfrac{Q}{\varepsilon _o}$

$E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

b) a < r < b

$E.ds=\dfrac{q_i}{\varepsilon _o}$

The total induce in this surface = - Q+ Q =0

$E.ds=\dfrac{0}{\varepsilon _o}$

E = 0

c) r > b

$E.ds=\dfrac{q_i}{\varepsilon _o}$

$E\times 4\pi r^2=\dfrac{Q}{\varepsilon _o}$

$E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

4 0

3 years ago

For the circuit shown, R = 75.0 ohms, L= 55.0 mg, and C = 25.0 μC. The power source has 12.0 V arms and a frequency of 60.0 Hz.

Natasha_Volkova [10]

Explanation:

Given that,

Resistance R = 75.0 ohms

Inductance L = 55.0 mH

Capacitance $C = 25.0\ \mu C$

Voltage V = 12.0 V

Frequency f = 60.0 Hz

We need to calculate the angular frequency

Using formula of angular frequency

$\omega = 2\pi f$

Put the value into the formula

$\omega =2\times3.14\times60.0$

$\omega=376.8\ rad/s$

(a). We need to calculate the value of $X_{L}$

Using formula of $X_{L}$

$X_{L}=\omega\times L$

Put the value into the formula

$X_{L}=376.8\times55.0\times10^{-3}$

$X_{L}=20.724\ \Omega$

(b). We need to calculate the value of $X_{L}$

Using formula of $X_{C}$

$X_{C}=\dfrac{1}{\omega C}$

$X_{C}=\dfrac{1}{376.8\times25.0\times10^{-6}}$

$X_{C}=106.16\ \Omega$

(c). We need to calculate the value of Z

Using formula of impedance

$Z=\sqrt{R^2+(X_{L}-X_{C})^2}$

Put the value into the formula

$Z=\sqrt{75.0^2+(20.724-106.16)^2}$

$Z=113.68\ \Omega$

(d). We need to calculate the rms current

Firstly we need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

Put the value into the formula

$I=\dfrac{12.0}{75.0}$

$I=0.16\ A$

Using formula of rms current

$I_{rms}=\dfrac{I_{0}}{\sqrt{2}}$

$I_{rms}=\dfrac{0.16}{\sqrt{2}}$

$I_{rms}=0.113\ A$

(e). We need to calculate the rms voltage across the resistor

Using formula of rms voltage

$V_{rms}=I_{rms}\times R$

$V_{rms}=0.113\times75.0$

$V_{rms}=8.475\ V$

(f). We need to calculate the rms voltage across the inductor

Using formula of rms voltage

$V_{rms}=I_{rms}\times X_{L}$

$V_{rms}=0.113\times20.724$

$V_{rms}=2.342\ V$

(g). We need to calculate the rms voltage across the capacitor

Using formula of rms voltage

$V_{rms}=I_{rms}\times X_{C}$

$V_{rms}=0.113\times106.16$

$V_{rms}=11.99\ V$

(h). We need to calculate the dissipated power by the circuit

Using formula of dissipated power

$P=RI^2$

Put the value into the formula

$P=75.0\times0.113^2$

$P=0.958\ W$

Hence, This is the required solution.

3 0

3 years ago

A hot air balloon is moving at a speed of 10 meters/second in the +x direction. The balloonist throws a brass ball with a veloci

hoa [83]

Answer:

160 meters

Relative of speed Vr = 10 -2 = 8 m/s (horizontal speed)

20 sec * 8 m/s = 160 m since ball travels 20 sec

4 0

3 years ago

A ball initially at rest rolls down a hill and has an acceleration of 3.3 m/s2. If it accelerates for 7.5 s, how many meters wil

ollegr [7]

The distance the ball rolls is given by

<em>x</em> = 1/2 <em>a</em> <em>t</em>²

so that

<em>x</em> = 1/2 * (3.3 m/s²) * (7.5 s)² = 92.8125 m ≈ 93 m

8 0

4 years ago