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pav-90 [236]
3 years ago
9

NEED HELP ASAP

Physics
1 answer:
bogdanovich [222]3 years ago
5 0
The equation for gravity is given by:

F_G =  \frac{G m_1 m_2}{r^2}

1. If r goes up by a factor of 3, gravity goes down by a factor of 9.
2. If m₁*m₂ goes up by a factor of 24, gravity goes up by a factor of 24.
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Name the type of component that has a greater resistance as the current through it increases​
Gnesinka [82]

Answer:

filament bulb, filament lamp

Explanation:

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Thanks+BRAINLIST
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Answer:

it change speed

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Which best explains why people see carrots as orange
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4 years ago
Read 2 more answers
A positive point charge Q1 = 2.5 x 10-5 C is fixed at the origin of coordinates, and a negative point charge Q2 = -5.0 x 10-6 C
mario62 [17]

Answer:

3.62 m  and - 1.4 m

Explanation:

Consider a location towards the positive side of x-axis beyond the location of charge Q₂

x = distance of the location from charge Q₂

d = distance between the two charges = 2 m

For the electric field to be zero at the location

E₁ = Electric field by charge Q₁ at the location = E₂ = Electric field by charge Q₂ at the location

\frac{kQ_{1}}{(2 + x)^{2}}= \frac{kQ_{2}}{x^{2}}

\frac{2.5\times 10^{-5}}{(2 + x)^{2}}= \frac{5 \times 10^{-6}}{x^{2}}

x = 1.62 m

So location is 2 + 1.62 = 3.62 m

Consider a location towards the negative side of x-axis beyond the location of charge Q₁

x = distance of the location from charge Q₁

d = distance between the two charges = 2 m

For the electric field to be zero at the location

E₁ = Electric field by charge Q₁ at the location = E₂ = Electric field by charge Q₂ at the location

\frac{kQ_{1}}{(x)^{2}}= \frac{kQ_{2}}{ (2 + x)^{2}}

\frac{2.5\times 10^{-5}}{(x)^{2}}= \frac{5 \times 10^{-6}}{(2+x)^{2}}

x = - 1.4 m

6 0
4 years ago
Ok, so this question is probably really easy but I can't really be bothered to answer it, terrible I know, but I thank all usefu
Dvinal [7]
Without a bulb energy cant go through and it would be an open circuit blocking the energy from coming out.
3 0
3 years ago
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