A motorcycle is following a car that is traveling at a constant speed on a straight highway. Initially, the car and the motorcyc
le are both traveling at the same speed of 19.0 m/s, and the distance between them is 52.0 m. After t1 = 5.00 s, the motorcycle starts to accelerate at a rate of 5.00 m/s2. How long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car?
1 answer:
Answer:
t=2.14s
Explanation:
Since it asks us for the time it takes from the moment it starts accelerating, the first 5 seconds of movement mentioned is irrelevant here.
Next it'd be simple just to use the kinematic equation involving distance, time, and velocity:
∆d=V₀t+at²/2
From here we can move the change in distance over and use the quadratic formula to solve for time.
My work is in the attachment. Comment with any questions.
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Answer:
10 m/s
Explanation:
Kinetic energy= mv² where m is mass and v is velocity.
We have to make v the subject so we should rearrange the equation
K=mv²
v²= (use algebra)
v²= 7/0.5×0.140
v²=100
v=√100
v=10 m/s
We can confirm this by using the kinetic energy formula.
K=×0.140×10²
K= 7 J
Hence it is proved that velocity is 10 m/s