Answer:
Vertex Distance to Vertex Distance to
A 3.6 AEF 3.6
B 2.2 BEF 2.2
C 2.0 CEF 2.0
D 3.4 DEF 3.4
Step-by-step explanation:
The Pythagorean's Theorem for our situation would look like this:

So let's call the short leg s, the long leg l and the hypotenuse h. It appears that all our measurements are based on the measurement of the short leg. The long leg is 4 more than twice the short leg, so that expression is l=2s+4; the hypotenuse measure is 6 more than twice the short leg, so that expression is h=2s+6. And the short leg is just s. Now we can rewrite our formula accordingly:

And of course we have to expand. Doing that will leave us with

Combining like terms we have

Our job now is to get everything on one side of the equals sign and solve for s

That is now a second degree polynomial, a quadratic to be exact, and it can be factored several different ways. The easiest is to figure what 2 numbers add to be -8 and multiply to be -20. Those numbers would be 10 and -2. Since we are figuring out the length of the sides, AND we know that the two things in math that will never EVER be negative are time and distance/length, -2 is not an option. That means that the short side, s, measures 10. The longer side, 2s+4, measures 2(10)+4 which is 24, and the hypotenuse, 2s+6, measures 2(10)+6 which is 26. So there you go!
We first do:
∅ = sin⁻¹(0.3)
∅ = 17.5°
To go into the second quadrant, we add 90°.
∅ = 17.5 + 90
= 107.5°
The answer is A.
A is x times larger than B
4*10^-3=x times larger than 4*10^-4
4*10^-3=x*4*10^-4
divide both sides by 4
10^-3=x*10^-4
divide both sides by 10^-4
10^1=x
10^1=10
answer is 10 times or C
Answer:
M: (-7, -3)
A: (0, -3)
T: (0, -8)
Step-by-step explanation:
each of the points are associated with a letter. you can find the points by looking at the points it matches up with in the formatting of (x,y)
for example, for M, you can see that the dot on the x axis seems to be hovering below -7, on the y axis, it seems to be hovering next to -3. therefore, its (-7,-3)