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kirza4 [7]
2 years ago
15

Can someone please answer this? Thank you

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
4 0

Answer:

1 63/80 or 1.7875

Step-by-step explanation:

2/4 + 18/5 + 28/10 + 5/20

First find a common denominator (20)

10/20 + 72/20 + 56/20 + 5/20 = 143/20

Then you divide that by 4 which is the number of the set of numbers you are given.

(143/20)/4= 1 63/80

Answer: 1 63/80 or 1.7875

TEA [102]2 years ago
3 0
The mean is 7.15 or 7 15/100. Hope this is correct, and please pick me brainliest!!!
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Y=4x-18<br><br> Find ordered pairs of intercepts of each line
Masja [62]

The ordered pairs for the intercepts are as follows:

x intercept = 9/2

y intercept = -18

In order to find either of these you must put 0's in for the other variable. So, to find the x intercept, we start by putting 0 in for y.

y = 4x - 18

0 = 4x - 18

-4x = -18

x = 9/2

To find the y intercept, we put a 0 in for x.

y = 4x - 18

y = 4(0) - 18

y = 0 - 18

y = -18

5 0
2 years ago
Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find
Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk x^2+y^2\le3, I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere x^2+y^2+z^2=3.

a. Let C denote the hemispherical <u>c</u>ap z=\sqrt{3-x^2-y^2}, parameterized by

\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k

with 0\le u\le2\pi and 0\le v\le\frac\pi2. Take the normal vector to C to be

\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k

Then the upward flux of \vec F=(2z+2)\,\vec k through C is

\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du

\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du

=\boxed{2(3+2\sqrt3)\pi}

b. Let D be the disk that closes off the hemisphere C, parameterized by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

with 0\le u\le\sqrt3 and 0\le v\le2\pi. Take the normal to D to be

\vec s_v\times\vec s_u=-u\,\vec k

Then the downward flux of \vec F through D is

\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv

=\boxed{-6\pi}

c. The net flux is then \boxed{4\sqrt3\pi}.

d. By the divergence theorem, the flux of \vec F across the closed hemisphere H with boundary C\cup D is equal to the integral of \mathrm{div}\vec F over its interior:

\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV

We have

\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2

so the volume integral is

2\displaystyle\iiint_H\mathrm dV

which is 2 times the volume of the hemisphere H, so that the net flux is \boxed{4\sqrt3\pi}. Just to confirm, we could compute the integral in spherical coordinates:

\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi

4 0
3 years ago
What is x minus 3 over x^2 minus 25 over x^2 minus 9 over x minus 5?
hichkok12 [17]
....................

6 0
3 years ago
Please help! If you do you will get 'Brainliest'
aalyn [17]

Answer:

B

Step-by-step explanation:

This is because 1/2 down from 1 1/2 is 1 then go 2 down on the number lone and you get 1 (B)

5 0
2 years ago
Read 2 more answers
Figure A is a scale image of figure B. Figure A maps to figure B with a scale factor of 2/3. What is the value of x?
trasher [3.6K]

9514 1404 393

Answer:

  x = 7

Step-by-step explanation:

10.5 maps to x with a scale factor of 2/3:

  x = 10.5 × 2/3

  x = 7

6 0
3 years ago
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