Answer:
kathryn= 6 years old
her mother= 38 years old
Step-by-step explanation:
kathryn=x
mother= x²+2
x²+2 +x=44
x=6
kathryn= 6 years old
her mother= 38 years old
Answer:
1036 students
Step-by-step explanation:
Let the number of students at West High be "w" and the number of students at East High be "e"
West High population is 250 FEWER than TWICE of East High, we can write:
w = 2e - 250
Total students in both schools is 2858, so we can write 2nd equation as:
e + w = 2858
We can replace 1st equation in 2nd to get an equation in e, and find "e":
e + w = 2858
e + (2e - 250) = 2858
3e - 250 = 2858
3e = 2858 + 250
3e = 3108
e = 3108/3
e = 1036
Hence,
number of students attending East High School = 1036 students
Answer:
c is the answer
Step-by-step explanation:
solution
therefore the equation is not true
The answer would be 40
5 divided by 1/8
5/1 divided by 1/8
5/1 divided by 8/1
then you would multiply
5 times 8
=40/1 or 40
Answer:
y=mx+c
We have to find the value of m and c.
Let's substitute the value of x and y from the table.
When x=1, y=15,
15= m(1)+c
m +c= 15 ------(1)
Now substitute another set of x and y values.
When x=2, y=24,
24= m(2)+c
2m +c= 24
c= 24 -2m ------(2)
Let me rewrite the two equations so that it is clearer for you to see.
m + c= 15 -----(1)
c = 24 -2m -----(2)
subst. (2) into (1):
m+ 24-2m= 15
-m= 15-24 (bring constants to 1 side, m terms to the other)
-m= -9 (simplify)
m= 9 ( divide by -1 throughout)
subst. m=9 into (2):
c= 24 -2(9)
c= 24-18
c= 6
Thus, the equation is y=9x+6.
When the cat is 3 years old, x=3.
When x=3,
y= 9(3)+6
y= 33.
Hence, the cat is 33 years old in human years.
