We are given polynomial:
.
We need to explain why the binomial (x + 2) IS a factor of this polynomial expression and why the binomial (x + 1) IS NOT a factor of this polynomial expression.
Let us set first factor equal to 0 and solve for x.
x+2=0
x=-2.
Plugging x=-2 in given polynomial, we get



<em>Because x=-2 gives 0 on plugging in given polynomial, so it's factor of given polynomial expression.</em>
Now, let us check second factor x+1=0
x=-1.
Plugging x=-1 in given polynomial, we get

=-5+8+7-6.
= -4.
<em>Because x=-1 doesn't gives 0 on plugging in given polynomial, so it's not a factor of given polynomial expression.</em>
Easy, subsitute a point
we see it goes through (0,4)
so subsitte 0 for x and see if we get 4
4^0=1, nope
4^0-3=1-3=-2, nope
4^0+3=1+3=4, yep
4^(0+3)=4^3=64, noe
answer is 3rd option
f(x)=4^x+3
Answer:
Step-by-step explanation:
Its may be a
The answer is 15x+7! :)
14x+x=15x and there is no other numbers that 7 can be added or subtracted by.
Answer:
x= -1
Step-by-step explanation:
-4(2x+5)+x+2= -11
-8x-20+x+2
-7x-18= -11
+18 +18
-7x= 7
-7x/-7 =7/-7
x= -1
Hope this helps!