Question

What is the factorization of 1000x^6 - 27?

Answer 1

Answer:

B

Step-by-step explanation:

Cube root 1000x^6 = 10x^2

Cube root of - 27 = 3

So the first part of the factorization process is 10x^2 - 3. There is no help here because all of the answers give this binomial as the first factor.

The second factor is (10x^2)^2 + (3)*10x^2 + 3^2)

Expanding you get 100x^4 + 30x^2 + 9

Be very careful when looking at 100x^4 because that is where the answer is found.

It has to be B