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liubo4ka [24]
3 years ago
6

What force is at least partially responsible for changing the energy of an object pushed off an edge A.Friction B. Gravity C.Air

resistance
Chemistry
1 answer:
svet-max [94.6K]3 years ago
7 0

Gravity force is at least partially responsible for changing the energy of an object pushed off an edge.

Explanation:

  • Gravity or gravitation, it is a phenomenon by the things with mass or energy including stars, galaxies, planets, and even light are taken to one another.
  • The gravitational pull of the Universe's initial gaseous matter caused it to begin to coalesce and form stars, which caused the stars to gather together into galaxies, and gravity is responsible for all of the Universe's large-scale structures.
  • Gravity has an unlimited range, but its effects are becoming ever weaker as items get away further.

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Equal volumes of H2 and O2 are placed in a balloon and then ignited. Assuming that the reaction goes to completion, which gas wi
Sonbull [250]

Answer: Oxygen

Explanation:

2H_2+O_2\rightarrow 2H_2O

As seen from the balanced equation:

2 moles of hydrogen combine with 1 mole of oxygen or 1 mole of hydrogen combine with 1/2 mole of oxygen.

According to Avogadro's law, equal volumes of gases contain equal number of molecules and hence equal number of moles.

Thus if x moles of both gases are present, x moles of hydrogen will combine with \frac{x}{2} moles of oxygen and  x-\frac{x}{2}=\frac{x}{2} moles of oxygen will be left used and will be in excess.

7 0
3 years ago
What is the mass of carbon dioxide formed when 36g of carbon is burnt?<br> C+O2 -------&gt;C02
Anestetic [448]

Answer:

Mass = 132 g

Explanation:

Given data:

Mass of CO₂ formed = ?

Mass of C burnt = 36 g

Solution:

Chemical equation:

C + O₂    →    CO₂

Number of moles of carbon:

Number of moles = mass/molar mass

Number of moles = 36 g/ 12 g/mol

Number of moles = 3 mol

now we will compare the moles of carbon and carbon dioxide.

                C           :        CO₂

                 1           :         1

                3           :         3

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 3 mol × 44 g/mol

Mass = 132 g

7 0
3 years ago
The following sequence of reactions occurs in the commercial production of aqueous nitric acid: 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l)ΔH=
castortr0y [4]

Answer:

The total energy change for the production of one mole of aqueous nitric acid is −494 kJ

Explanation:

<u>Step 1</u>: Data given

4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l)ΔH=−907kJ 2NO(g)+O2(g)⟶2NO2(g)ΔH=−113kJ 3NO2+H2O(l)⟶2HNO3(aq)+NO(g)ΔH=−139kJ

<u>Step 2:</u> Multiply equations

Multiply the first equation by 3:

12 NH3(g) + 15 O2(g) → 12 NO(g) + 18 H2O(l) ΔH = −2721 kJ

Multiply the second equation by 6:

12 NO(g) + 6 O2(g) → 12 NO2(g) ΔH = −678 kJ

Multiply the third equation by 4:

12 NO2(g) + 4 H2O(l) → 8 HNO3(aq) + 4 NO(g) ΔH = −556 kJ

<u>Step 3:</u> Get the equations together

12 NH3(g) + 15 O2(g) + 12 NO(g) + 6 O2(g) + 12 NO2(g) + 4 H2O(l) →

12 NO(g) + 18 H2O(l) + 12 NO2(g) + 8 HNO3(aq) + 4 NO(g)

ΔH = −2721 kJ − 678 kJ − 556 kJ

We can simplify as followed:

12 NH3(g) + 21 O2(g) → 14 H2O(l) + 8 HNO3(aq) + 4 NO(g) ΔH = −3955 kJ

<u> Step 4:</u> Determine the total energy change for the production of one mole of aqueous nitric acid by this process:

−3955 kJ/8 moles HNO3= −494 kJ

The total energy change for the production of one mole of aqueous nitric acid is −494 kJ

3 0
3 years ago
Which statement best describes a solution containing a strong base?
Scilla [17]
B. The solution is concentrated
4 0
4 years ago
A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97. ??. Unfortunately, a car
serg [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

 Answer: 760 uM

Explanation:

the addition of solvent to a solution in a such away that the volume of the solution increases and the concentration decreases is a process know as dilution

The concentration and the volume of the dilute and concentrated solution are given below as follows

     C_{1}V_{1}                               = C_{f}V_{f}

Concentrated solution          Dilute solution

Given that  M1 = 97.0uM

                  V1 = 47.0 mL

                 V2 = 6.0 mL

                 M2  = ?

Therefore M1V1   = M2V2

                M2      = M1V1/V2

                 M2 = (97*47)/6

               M2 = 760 uM

Answer: 760 uM

               

5 0
4 years ago
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