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11Alexandr11 [23.1K]
3 years ago
8

Luis set a glass of ice water out side is the sunshine . when he looked at the glass 10 minutes later, the contents had changed.

what kind of change happened to the ice water?
A.evaperation
B.conduction
C.chemical change
d.sudden change
Chemistry
2 answers:
abruzzese [7]3 years ago
8 0

well its evaporation cuz it the suns heat heated the ice to the point where it turned to a gas, it could be conduction cuz the heat of the sunshine conducted the ice and turned it to a gas but that would be evaporation too so its not onduction, its not a chemical change cuz theres no new molecule the substance is itself, and its not a sudden change obviously

so the answer is A. evaporation~~~

andrew11 [14]3 years ago
3 0

Evaporation. The sun took up water, which forms clouds then rains/snows

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<u>Answer:</u> The value of <em>i</em> is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

<u>Explanation:</u>

The equation used to calculate the Vant' Hoff factor in dissociation follows:

\alpha =\frac{i-1}{n-1}

where,

\alpha = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4

The equation used to calculate the degee of dissociation follows:

\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

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3 years ago
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Answer:

156,4 g of sodium formate

Explanation:

The pka of the formic acid is 3,74. Using Henderson-Hasselbalch formula:

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Where A⁻ is the conjugate base (Formate) and HA is the formic acid.

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That means you need 2,30 moles of formate (Sodium formate), to produce the desired buffer. As the molar mass of sodium formate is 68,01g/mol, the weight of sodium formate that must be added is:

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