Given:
A line passes through (-5,-3) and perpendicular to 
.
To find:
The equation of the line.
Solution:
We have,
On comparing this equation with slope intercept form, i.e., 
, we get
It means, slope of this line is 
.
Product of slopes of two perpendicular lines is always -1.
Slope of required line is 
and it passes through the point (-5,-3). So, the equation of the line is
where, m is slope.
Therefore, the equation of required line is 
.
Answer:
See explanation.
Step-by-step explanation:
2) Your written answer is correct, y = x +4
3) Slope of perpendicular line: 5/2
y=mx+b
4 = (5/2)(4) + b
4 = 10 + b
b = -6
So, y=(5/2)x - 6
4) Slope of perpendicular line: 1
y=mx+b
5 = (1)(4) + b
5 = 4 + b
b = 1
So, y = x + 1
7) Slope of perpendicular line: 3/4
y=mx+b
4 = (3/4)(4) + b
4 = 3 + b
b = 1
So, y = (3/4)x + 1
8) Slope of perpendicular line: 1/4
y=mx+b
-2 = (1/4)(0) + b
b = -2
So, y = (1/4)x - 2
Ya that's correct u got the right answer
A 42 24÷16 =1.5 1.5×28 =42 b i think its 78.4 im not sure
