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fomenos
2 years ago
6

George manages inventory for a company. The company has been struggling to reduce production costs in all departments for severa

l months. What inventory management technique can George adopt to reduce storage costs without affecting the production flow?
Business
1 answer:
Liula [17]2 years ago
7 0

Answer:

The Just-in-time( JIT) inventory management

Explanation:

The Just-in-time( JIT) inventory management approach seeks to increase efficiency in the stock management process. JIT achieves efficiency by reducing the cost of holding stocks and eliminating wastage associated with keeping a high volume of inventory.  Under JIT, materials are ordered when they are required for production. The business does hold stocks or will have minimal quantities in the stores.

George can adopt the just-in-time system in his place of work. His cost of holding stock will reduce as materials will be purchased to meet the current production requirements.  Market demand  determine production. It means there will be no storage of a high volume of finished goods, which ties up a lot of capital.

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Concord Company is constructing a building. Construction began on February 1 and was completed on December 31. Expenditures were
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$2,317,000

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8 0
3 years ago
A company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x)=14,000ln(0.01x+1). Use the diffe
melamori03 [73]

Answer: The change in revenue for the sale of 1 more doghouse $ 66.67 dollars

Explanation: Differential is a function that can be used to approximate function value with a great degree of accuracy. This is done by the following.

Mathematical definition of derivative: f'(x) = lim f(x+Δx) - f(x)/Δx.

If Δx is very small:

f'(x) . Δx ≅ f(x+Δx) - f(x)

Knowing that Δy ≅ f(x+Δx) - f(x) and the diferential of variable x can be written by dx as the variable y can be dy:

dy = f'(x) dx

which means that the differential dy is approximately equal to the change Δy, if Δx is very small.

For the question, R(x) = y(x) = 14,000ln(0.01x+1)

f'(x) = \frac{d[14,000.ln(0.01x+1)]}{dx}

Using the chain rule, the derivative will be:

f'(x) = 14,000.\frac{0.01}{0.01x+1}

dy = 14,000.\frac{0.01}{0.01x+1}.dx

dx is the change in x. For the question, the change is 1 (1 more doghouse) and x is 110:

dy = 14,000\frac{0.01}{0.01.110+1}.1

dy = \frac{140}{2.1}

dy = 66.67

The change in revenue is $66.67 dollars.

5 0
2 years ago
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