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IgorC [24]
3 years ago
11

What do you know about the scale factor for the dilation shown? Explain.

Mathematics
2 answers:
BARSIC [14]3 years ago
4 0

Answer:A

Step-by-step explanation:

Leto [7]3 years ago
4 0

Answer:

The scale factor is between 0 and 1 because the image is a reduction of the pre-image.

Step-by-step explanation:

got it straight from ed

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Asa received scores of 72, 97, and 82 on her last three math tests. she needs a mean test score of 82 to qualify for the math te
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First step is to find what should be the required total of sum of Score after fourth test, to identify how much more or less she need to score in his fourth test.

Since Mean = (Sum of Scores)/number of test

using above formula we determine what is the required sum of score.

82 = (Sum of Scores)/4

⇒ 82 × 4 = 328

So in four test she should have score total as 328

So Score require in fourth test = Required Score Total - (total score in 3 tests)

             = 328 - ( 72 + 97 + 82 ) = 77

So she need score of 77 to be at mean of 82 after fourth test and get qualify for the team


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3 years ago
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What is the simplified version of 3\sqrt{135}
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Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

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Help me, please. Confused again.
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Answer:

b

Step-by-step explanation:

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