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3 years ago

A force that results from charged particles is called?

Physics

2 answers:

olchik [2.2K]3 years ago

7 0

A force that results from charged particles is called "electrostatic force".

Hope this helps!

-Thanks!

-Charlie

inessss [21]3 years ago

3 0

Answer:

Electrostatic force

Explanation:

The force that acts between charged particles is called electrostatic force. Its magnitude is given by:

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the magnitudes of the two charges

r is the distance between the two charges

Concerning the direction of the force:

- The force is attractive when the two charges have opposite signs, and

- The force is repulsive when the two charges have same sign

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4 years ago

Aparticlewhosemassis2.0kgmovesinthexyplanewithaconstantspeedof3.0m/s along the direction r = i + j . What is its angular momentu

svetoff [14.1K]

Answer:

$\vec{L}=-30\frac{kgm^2}{s}\hat{k}$

Explanation:

In order to calculate the angular momentum of the particle you use the following formula:

$\vec{L}=\vec{r}\ X\ \vec{p}$ (1)

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p is the linear momentum vector and it is given by:

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the direction of p comes from the fat that the particle is moving along the i + j direction.

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3 years ago

The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o

LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

$\bar F \cdot \Delta t = m \cdot (v_{2}-v_{1})$ (1)

Where:

$\bar F$ - Average impact force, in newtons.

$\Delta t$ - Duration of the impact, in seconds.

$m$ - Mass of the sledge hammer, in kilograms.

$v_{1}$ , $v_{2}$ - Initial and final velocity, in meters per second.

If we know that $\Delta t = 0.0020\,s$ , $m = 4\,kg$ , $v_{1} = -6\,\frac{m}{s}$ and $v_{2} = 0\,\frac{m}{s}$ , then we estimate the average impact force is: