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san4es73 [151]
3 years ago
9

When a rattlesnake strikes, its head accelerates from rest to a speed of 28 m/s in 0.65 seconds. Assume for simplicity that the

only moving part of the snake is its head of mass 170 g. How much (average) power does the rattlesnake need to accelerate its head that fast
Physics
1 answer:
enyata [817]3 years ago
7 0

Answer:

102.52 W

Explanation:

Power: This ca be defined as the rate at which energy is used up.

The S.I unit of power is Watt(W).

From the question,

P = E/t.............. Equation 1

Where P = average power of the snake head, E = energy of the snake, t = time.

But,

E = 1/2mv²............ Equation 2

Where m = mass of the head, v = velocity of the snake head.

Substitute equation 2 into equation 1

P = 1/2mv²/t ............ Equation 3

Given: m = 170 g = 0.17 kg, v = 28 m/s, t = 0.65 s.

Substitute into equation 3

P = 1/2(0.17)(28²)/0.65

P = 102.52 W.

Hence the average power of the snake = 102.52 W

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horrorfan [7]

Answer:

f = 12 cm

Explanation:

<u>Center of Curvature</u>:

The center of that hollow sphere, whose part is the spherical mirror, is known as the ‘Center of Curvature’ of  mirror.

<u>The Radius of Curvature</u>:

The radius of that hollow sphere, whose part is the spherical mirror, is known as the ‘Radius of Curvature’ of  mirror. It is the distance from pole to the center of curvature.

<u>Focal Length</u>:

The distance between principal focus and pole is called ‘Focal Length’. It is denoted by ‘F’.

The focal length of the spherical (concave) mirror is approximately equal to half of the radius of curvature:

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where,

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Therefore,

f = \frac{24\ cm}{2}

<u>f = 12 cm</u>

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3 years ago
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
GuDViN [60]

Answer:

Q = 12540  J

Explanation:

It is given that,

Mass of water, m = 50 mL = 50 g

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Put all the values,

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7 0
3 years ago
In designing circular rides for amusement parks, mechanical engineers must consider how small variations in certain parameters c
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Answer:

Part a)

dF = -\frac{mv^2}{r^2} dr

Part b)

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Explanation:

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As we know that force on the passenger while moving in circle is given as

F = \frac{mv^2}{r}

now variation in force is given as

dF = -\frac{mv^2}{r^2} dr

here speed is constant

Part b)

Now if the variation in force is required such that r is constant then we will have

F = \frac{mv^2}{r}

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dF = \frac{2mvdv}{r}

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3 years ago
A yo‑yo with a mass of 0.0800 kg and a rolling radius of =2.70 cm rolls down a string with a linear acceleration of 5.70 m/s2.
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Explanation:

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