Question

Identify the vertex and the y-intercept of the graph of the function y= -0.25(x-4)-2

Answer 1

Answer:

the vertex is (4, -2) and y-intercept is -6

Step-by-step explanation:

we need to identify the vertex and the y-intercept of the given function

$y=-0.25(x-4)^{2}-2$

Since, In general the equation of parabola

$y=a(x-h)^{2}+k$ where (h,k) is vertex of parabola

Compare $y=-0.25(x-4)^{2}-2$ with $y=a(x-h)^{2}+k$

so, the vertex is (4, -2)

and y-intercept is find by put x=0 in equation

$y=-0.25(0-4)^{2}-2$

$y=-0.25(4)^{2}-2$

$y=-0.25(16)-2$

$y=-4-2$

$y= -6$

Therefore, the vertex is (4, -2) and y-intercept is -6

Answer 2

The y intercept is -2, but I don't remember how to find the vertex sorry