Question

0.632 mole of carbon dioxide is produced in a chemical reaction at STP. What

Answer 1

Answer:

V = 14.2 L

Explanation:

Given data:

Moles of CO₂ = 0.632 mol

Temperature = standard = 273 K

Pressure = standard = 1 atm

Volume of gas = ?

Solution;

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.632 mol ×0.0821 atm.L/ mol.K × 273 K / 1 atm

V = 14.2 L/ 1

V = 14.2 L