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3 years ago

The sum of the oxidation numbers of all atoms in a neutral compound is

Chemistry

2 answers:

Phoenix [80]3 years ago

5 0

The sum of the oxidation numbers of all atoms in a neutral compound is zero.

Olenka [21]3 years ago

5 0

If a compound is neutral its sum of oxidation numbers must be 0 for example Ca (2+) + O (-2) = CaO

hope that helps

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Answer:

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$\Delta H_v=RT_b\left [ \frac{3.974\left ( \frac{T_b}{T_c} \right )-3.958+1.555lnP_c}{1.07-\left ( \frac{T_b}{T_c} \right )} \right ]$

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$\Delta H_v$ is the Heat of vaoprization (J/mol)

$T_b$ is the normal boiling point of the gas (K)

$T_c$ is the Critical temperature of the gas (K)

$P_c$ is the Critical pressure of the gas (bar)

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$T_b=307.4\ K$

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Applying the above equation to find heat of vaporization as:

$\Delta H_v=8.314\times307.4 \left [ \frac{3.974\left ( \frac{307.4}{466.7} \right )-3.958+1.555ln36.4}{1.07-\left ( \frac{307.4}{466.7} \right )} \right ]$

$\Delta H_v=26400 J/mol$

The conversion of J into kJ is shown below:

1 J = 10⁻³ kJ

Thus,

$\Delta H_v=26.4 kJ/mol$

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