Take 5.25 grams and give it proportionally to the carbon
0.9226 * 5.25 grams = 4.84 grams Carbon
Find the number of moles
(4.84 grams carbon)/(12.01 grams/mol) = 0.403 moles Carbon
The number of atoms in a mole of a substance is called Avogadro's number.
There are 6.022 * 10^23 atoms in one mole of anything
(0.403 moles Carbon) * (6.022 * 10^23 atoms/mole) = 2.43 * 10^23 atoms of Carbon
Answer:
When there remains one-quarter of the sample, the age of the sample is 10940 years
Explanation:
<u>Step 1:</u> Data given
The half-life of C-14 is 5470 years.
The half- life time is the time required for a quantity to reduce to half of its initial value.
This means after 5470 years there remains half of the C-14 sample.
To remain a quarter of the sample, another cycle of 5470 years is required.
This means 2 half-lives should have passed to remain a quarter of the sample.
<u>Step 2</u>: Calculate it's age
t/(t/1/2) = 2
⇒ with t = the age (or time) of the sample
⇒ with t(1/2) = the half-life time of the sample = 5470 years
⇒ with 2 = the number of halvf- lives passed
t/5470 = 2
t = 2*5470 = 10940 years
When there remains one-quarter of the sample, the age of the sample is 10940 years
Frequency= 1/period
hence ans= 1/0.25
= 4s
We can tell which acid which have the highest percent ionization on the basis of pH value.
<h3>What is percent ionization?</h3>
The % ionized indicates how much of the original chemical has ionized. As a result, we compare the ion concentration in solution to the neutral species' original concentration.
If any acid have a high pH value then they must show high percent ionization because they are strong in nature and show full dissociation.
Hence acids with high pH value will show highest percent ionization.
To know more about percent ionization, visit the below link:
brainly.com/question/3229194
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Answer:
a= 0.2m/s²
Explanation:
Fnet = ma
20 = 100a (divide both sides by 100)
a = 0.2m/s²
