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Masja [62]
2 years ago
6

Solutions with water as the solvent are called

Chemistry
1 answer:
Soloha48 [4]2 years ago
8 0

Answer:

C. Aqueous Solutions

General Formulas and Concepts:

<u>Aqueous Solutions</u>'

  • Dissociation
  • Solvents and Solutions

Explanation:

Water is the universal solution that solvents are dissolved in. Whenever anything is dissolved in water, it will be an aqueous solution.

Strong ionic solutions dissolve into their ions when dissolved in water.

Weak acids and bases don't fully dissociate in water.

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Answer:

The piece of wood will sink

Explanation:

If an object has a density higher than water, it will sink, and the piece of wood is more dense than water when measured.

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The matter through which waves travel is called a/an​
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A medium.

<h3>Explanation:</h3>

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The vapor pressure of benzene at 298 K is 94.4 mm of Hg. The standard molar Gibbs free energy of formation of liquid benzene at
horsena [70]

Answer:

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

Explanation:

Bringing out the parameters mentioned in the question;

Vapor pressure = 94.4 mm of Hg

The vaporization reaction is given as;

C₆H₆(l) ⇄ C₆H₆(g)

Equilibrium in terms of activities is given by:

K = a(C₆H₆(g)) / a(C₆H₆(l))

Activity of pure substances is one:

a(C₆H₆(l)) = 1

Assuming ideal gas phase activity equals partial pressure divided by total pressure. At standard conditions

K = p(C₆H₆(g)) / p°

Where p° = 1atm = 760mmHg standard pressure

We now have;

K = 94mmHg / 760mmHg = 0.12421

Gibbs free energy is given as;

ΔG = - R·T·ln(K)

where R = gas constant = 8.314472J/molK

So ΔG° of vaporization of benzene is:

ΔvG° = - 8.314472 · 298.15 · ln(0.12421)

ΔvG° = 5171J/mol = 5.2kJ/mol  

Gibbs free energy change of reaction = Gibbs free energy of formation of products - Gibbs free energy of formation of reactants:

ΔvG° = ΔfG°(C₆H₆(g)) - ΔfG°(C₆H₆(l))

Hence:

ΔfG°(C₆H₆(g)) = ΔvG°+ ΔfG°(C₆H₆(l))

ΔfG°(C₆H₆(g)) = 5.2kJ/mol + 124.5kJ/mol

ΔfG°(C₆H₆(g)) = 129.7kJ/mol

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neonofarm [45]

Answer:

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