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fenix001 [56]
3 years ago
11

Select the correct answer.

Engineering
2 answers:
nata0808 [166]3 years ago
7 0
The correct answer is d
valentina_108 [34]3 years ago
6 0
D-regulatory controls
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Which allows a user to run applications on a computing device? Group of answer choices Application software CSS Operating system
sveticcg [70]

Answer:

The operating system

Explanation:

The job of the operating system is to manage system resources allowing the abstraction of the hardware, providing a simple user interface for the user.  The operating system is also responsible for handling application's access to system resources.

For this purpose, the operating system allows a user to run applications on their computing device.

Cheers.

4 0
3 years ago
You are traveling upstream on a river at dusk. You see a buoy with the number 5 and a flashing green light . What should you do?
nalin [4]

Answer:

please give brainliest my brother just got the corona virus

Explanation:

this is my brothers account he wants to get 5 brainliest

8 0
3 years ago
10 Khz is equivalent to all except<br> a 1 Mhz<br> b. 10 KHZ<br> c..01 Mhz<br> d. 10000 Hz
xenn [34]

Answer: A 1 MHz

Explanation:

10Khs equals to 10,000Hz/10Khz/0.01Mhz/0.00001Ghz

4 0
3 years ago
A circular pipe of 25-mm outside diameter is placed in an airstream at 25 °C and 1-atm pressure. The air moves in cross flow ove
Scrat [10]

Answer: a) Fd = 3.24 N/m

b) Q = 520 w/m

Explanation: please find the attached files for the solution

7 0
3 years ago
How many kg / day of NaOH must be added to neutralize a waste stream generated by an industry producing 90,800 kg / day of sulfu
hram777 [196]

Answer:

74.12kg/day

Explanation:

Equation of reaction for the neutralization reaction of sodium hydroxide and sulfuric acid: 2NaOH + H2SO4 yields Na2SO4 + 2H2O

Mass of sulfuric acid produced per day = 90,800kg

Percentage of sulfuric acid in wastewater = 0.1%

Mass of sulfuric acid that ends up in wastewater per day = 0.1/100 × 90,800 = 90.8kg

From the equation of reaction, 2 moles of NaOH (80kg of NaOH) is required to neutralize 1 mole of H2SO4 (98kg of H2SO4)

80kg of NaOH is required to neutralize 98kg of sulfuric acid

90.8kg of sulfuric acid would be neutralized by (90.8×80)/98kg of NaOH = 74.14kg/day of NaOH

7 0
3 years ago
Read 2 more answers
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