Answer:
36V, 100A-hr
Explanation:
Since the batteries are connected in series;
i. the output voltage will be the sum of the individual voltages
ii. the current rating (A-hr) will be the same as their individual current rating (A-hr). And this is because the same current flows through the batteries.
From i,
The output voltage, V, is given by the sum of the voltages of the three batteries;
V = 12V + 12V + 12V
V = 36V
From ii,
The A-hr capacity of the connection is the same as that of the individual batteries;
100 A-hr
Therefore, the output voltage and A-hr capacity of this connection is:
36V, 100A-hr
Answer:
The FEM is a general numerical method for solving partial differential equations in two or three space variables (i.e., some boundary value problems). To solve a problem, the FEM subdivides a large system into smaller, simpler parts that are called finite elements.
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Answer:
Given that;
Jello there, see explanstion for step by step solving.
A horizontal channel of height H has two fluids of different viscosities and densities flowing because of a pressure gradient dp/dx1. Find the velocity profiles of two fluids if the height of the flat interface is ha.
Explanation:
A horizontal channel of height H has two fluids of different viscosities and densities flowing because of a pressure gradient dp/dx1. Find the velocity profiles of two fluids if the height of the flat interface is ha.
See attachment for more clearity
Answer:
(a) 120 kW
(b) 800 kW
Explanation:
Given:
diameter: 1.5 m
length = 22 m
U = 5 m/s
temperature = 20°C
For water at 20°C, take ρ = 998 kg/m³ and µ = 0.001 kg/m⋅s
To find:
power in kW
(a) if the cylinder is parallel
Length / Diameter = L / D = 22 / 1.5 = 14.6 = 15
Re(L) = ρ*U*L / µ = 998 * 5 * 22 / 0.001 = 109780000 = 1.1E8
C(D.Frontal) ≈ 1.1
Force = F = 1.1 * ρ/2 * U² * π / 4 * D
= 1.1 (998 / 2) (5)²(π / 4)(1.5)²
= 1.1 * 499 * 25 * 0.785 * 2.25
= 24000 N
Power = Force * Displacement / time
= F * U
= 24000 * 5
= 120000
Power = 120 kW
b) if the cylinder is normal to the tow direction.
Re(L) = ρ*U*D / µ = 998 * 5 * 1.5 / 0.001 = 7485000 = 7.5E6
C(D.Frontal) ≈ 0.4
Force = F = 0.4 * ρ/2 * U² * D * L
= 0.4 (998 / 2) (5)²(1.5)(22)
= 164670 ≈ 165000
Power = Force * Displacement / time
= F * U
= 165000 * 5 = 825000
≈ 800 kW
Power = 800 kW
