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3 years ago

How to find the length of AB

Mathematics

2 answers:

Andrej [43]3 years ago

6 0

Answer:

The answer is option C

Step-by-step explanation:

To find the length of AB we use sine

sin∅ = opposite / hypotenuse

From the question

The hypotenuse is AB

The opposite is AC

So we have

sin 54 = AC/AB

sin 54 = 16 / AB

AB = 16/sin 54

AB = 19.777

Hope this helps you

Alenkinab [10]3 years ago

6 0

Answer:

AB = 19.78

Step-by-step explanation:

From the diagram (Right-angle triangle):

AC = 16

AB = ?

Angle = 54°

Applying trig ratio:

Tan 54° = 16/BC

1.376381920 = 16/BC

Therefore;

BC = 16/1.376381920

BC = 11.62

To solve the length AB:

Cos 54° = BC/AB

0.587785252 = 11.62/AB

Solving AB gives:

AB = 11.62/0.587785252

AB = 19.78

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Determine the measure of each indicated angle. Show all necessary steps!

Mariana [72]

The measure of the unknown angle are; a) x = 89 degrees, b) p = 92 degrees.

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For a regular polygon of any number of sides, the sum of its exterior angle is 360°.

We already know that a 4-sided polygon's angles add up to 360 degrees.

So to find the value of x:

69 + 118 + 84 + x = 360

x = 360 - (69 + 118 + 84)

x = 89 degrees

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2 years ago

List four fractions that are equivalent to 3/5

kirill115 [55]

6/10, 9/15,12/20,15/25

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3 years ago

Read 2 more answers

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

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The answer to your problem is 11

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Answer:

Step-by-step explanation:

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