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kenny6666 [7]
3 years ago
5

How many terms are in the arithmetic sequence 1313, 1616, 1919, ……, 7070, 7373?

Mathematics
1 answer:
Nataliya [291]3 years ago
7 0
To find the number of terms in the arithmetic sequence, we need to use the formula 
a_{n}= a_{1}+(n-1)d    
where a_{n} is the nth number, a_{1} is the first number, n is the number of terms and d is the difference of the two consecutive numbers.
7373 = 1313 + (n - 1)(303)
7373 = 1313 + 303n - 303
7373 = 1010 + 303n
7373 - 1010 = 303n
6363 = 303n
6363 ÷ 303 = n
n = 21

Therefore, there are 21 terms in the arithmetic sequence given.
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The expression evaluates to 20

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<h3>State the property Modulus of the function - F(x) = x.</h3>

For a function f(x) = x, which is real in nature -

f(x) = |x| =  \left \{ {{-x\;\;\;for\;x < 0} \atop {x\;\;\;for\;x > 0}} \right.

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