(3+h)^3-27/h Lim--->0 help pls. ...?

Mathematics

1 answer:

iragen [17]3 years ago

7 0

[(3 + h)³ - 27]/h
= (27 + 27h + 9h² + h³ - 27) /h
= h(h² + 9h + 27)/h
= h² + 9h + 27
h → 0
= 0 + 0 + 27
= 27

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${\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}$

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