The height of the can for this case is given by:
h = 40 mm
The radius of the can is given by:
r = (1 3/8) * h
Substituting values:
r = (1 3/8) * 40
r = 55 mm
Therefore, the diameter of the can is:
d = 2 * r
d = 2 * 55
d = 110 mm
Answer:
The diameter of the can will be:
d = 110 mm
Answer:
51
Step-by-step explanation:
Hope this helps
<h2>
The top of the ladder is descending at 0.3 m/s.</h2>
Step-by-step explanation:
By Pythagoras theorem we know that
Hypotenuse² = Base² + Perpendicular²
h² = b² + p²
We have for ladder
h = 5 m
b = 3 m
5² = 3² + p²
p = 4 m
![\frac{db}{dt}=0.4m/s\\\\\frac{dh}{dt}=0](https://tex.z-dn.net/?f=%5Cfrac%7Bdb%7D%7Bdt%7D%3D0.4m%2Fs%5C%5C%5C%5C%5Cfrac%7Bdh%7D%7Bdt%7D%3D0)
Differentiating h² = b² + p² with respect to time
![2h\times \frac{dh}{dt}=2b\times \frac{db}{dt}+2p\times \frac{dp}{dt}\\\\5\times 0=3\times 0.4+4\times \frac{dp}{dt}\\\\\frac{dp}{dt}=-0.3m/s](https://tex.z-dn.net/?f=2h%5Ctimes%20%5Cfrac%7Bdh%7D%7Bdt%7D%3D2b%5Ctimes%20%5Cfrac%7Bdb%7D%7Bdt%7D%2B2p%5Ctimes%20%5Cfrac%7Bdp%7D%7Bdt%7D%5C%5C%5C%5C5%5Ctimes%200%3D3%5Ctimes%200.4%2B4%5Ctimes%20%5Cfrac%7Bdp%7D%7Bdt%7D%5C%5C%5C%5C%5Cfrac%7Bdp%7D%7Bdt%7D%3D-0.3m%2Fs)
The top of the ladder is descending at 0.3 m/s.