We have the following functions:
f (x) = x ^ 2 + 1
g (x) = 1 / x
Multiplying we have:
(f * g) (x) = (x ^ 2 + 1) * (1 / x)
Rewriting:
(f * g) (x) = ((x ^ 2 + 1) / x)
Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
We have then:
All reals except number 0
Answer:
b. all real numbers, except 0
Answer:
I think it is 3(x+1) not sure but try it(it is a graph answer)
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Answer:
Step-by-step explanation:
4*3^x+1=27+(3^2)^x
(3^2)^x=(3^x)^2
3^x=t
4t+1=27+t^2
t^2-4t+27-1=0
t^2-4t+26=0
delta=4^2-4*1*26=16-84=-68<0
the equation has not real solutions
