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r-ruslan [8.4K]
4 years ago
6

Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data

Mathematics
1 answer:
eduard4 years ago
3 0

Answer:

we need the data to answer the question

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Samuel collected 30 signatures from fifth-grade students at his school. He noticed that 3/5 of the signatures were done in penci
Iteru [2.4K]

Answer:

30 / 5 = 6.

6x3=18

Step-by-step explanation:

Hope this helped! Have a great day!

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3 years ago
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Keith_Richards [23]

a = v^2 / r

v^2 = ar

v = √ar

8 0
3 years ago
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Please answer ASAP Show work 5b=k-b
anzhelika [568]

Answer:

5 KiloBytes (KB) = 5,120 Bytes (B)

1 KB = 1,024 B

1 B = 0.000977 KB

Step-by-step explanation:

3 0
3 years ago
Help Needed <br>-Thanks<br>​
Gelneren [198K]

Answer:

− 2 √ 3

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

5 0
3 years ago
Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably infinite, exhib
anzhelika [568]

Answer:

a) Countably infinite

b) Countably infinite

c) Finite

d) Uncountable

e) Countably infinite

Step-by-step explanation:

a) Let S the set of integers grater than 10.

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(10+k)=k-1 for k\in\mathbb{Z}^+/\{0\}.

Let's see that the function is one-to-one.

Suppose that f(10+k)=f(10+j) for k≠j. Then k-1=j-1. Thus k-j=1-1=0. Then k=j. This implies that 10+k=10+j. Then the correspondence is injective.

b) Let S the set of odd negative integers

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(-(2k+1))=k.

Let's see that the function is one-to-one.

Suppose that f(-(2k+1))=f(-(2j+1)) for k≠j. By definition, k=j. This implies that the correspondence is injective.

c) The integers with absolute value less than 1,000,000 are in the intervals A=(-1.000.000, 0) B=[0, 1.000.000). Then there is 998.000 integers in A that satisfies the condition and 999.000 integers in B that satifies the condition.

d) The set of real number between 0 and 2 is the interval (0,2) and you can prove that the interval (0,2) is equipotent to the reals. Then the set is uncountable.

e) Let S the set A×Z+ where A={2,3}

Consider the following correspondence:

f: S\rightarrow \mathbb{Z}^+ defined by f(2,k)=2k, \;f(3,j)= 2j+1

Let's see that the function is one-to-one.

Consider three cases:

1. f(2,k)=f(2,j), then 2k=2j, thus k=j.

2. f(3,k)=f(3,j), then 2k+1=2j+1, then 2k=2j, thus k=j.

3.  f(2,k)=f(3,j), then 2k=2j+1. But this is impossible because 2k is an even number and 2j+1 is an odd number.

Then we conclude that the correspondence is one-to-one.

6 0
3 years ago
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