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Rufina [12.5K]
3 years ago
12

How many ways can David pick four of the first twelve positive integers such that no two of the numbers he picks are consecutive

?
Mathematics
1 answer:
vekshin13 years ago
6 0

Answer:

70 times

Step-by-step explanation:

5 consecutive even integers: 2n, 2n+2, 2n+4, 2n+6, 2n+8 for any integer n The sum of the two smallest of five consecutive even integers is 50 less than the sum of the other three integers: 2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 504n + 2 = 6n -3234 = 2nn = 17 The smallest integer in our sequence is 2n = 2*17 = 34 Check:2n + 2n+2 = 2n+4 + 2n+6 + 2n+8 - 5034 + 36 = 38 + 40 + 42 - 5070 = 120 - 5070 = 70

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Answer:

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Step-by-step explanation:

sub 2 into 1

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2 years ago
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2 years ago
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pochemuha
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Hello there!

Your answer is 3 hours and 30 minutes.

I hope I have been of assistance!

~ Fire
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