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riadik2000 [5.3K]

3 years ago

9

You have a photo that measures 1 in. wide by 3 in. tall. If you want to enlarge the photo so that the height is 18 in., what wil

l the width of the photo be?

1 answer:

kiruha [24]3 years ago

4 0

6in... 3 times 6 is 18, so 1 times 6 is 6

You might be interested in

Find the second derivative of 2x^3-3y^2=8

Umnica [9.8K]

Answer:

$\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

Step-by-step explanation:

<u>Find the first implicit derivative using implicit differentiation</u>

<u /> $2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}$

<u>Use the substitution of dy/dx to find the second derivative (d²y/dx²)</u>

<u /> $\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

5 0

3 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

(c) 0

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago

A rectangle has sides of length 7 in and 13 in. To the nearest degree, what angle does the diagonal make with the longer side?

Gala2k [10]

I think it’s D or maybe just maybe it’s will have to be B

7 0

4 years ago

I will give brainliest

mariarad [96]

Answer:

1. I need to see the table to answer that

2. I think you need to find the probability of getting 1, H. That probability is 1/10 which is also 10%.

3. can't answer a, but b is 1/14 or 7%

4. as a fraction= 1/6

as a percent= 17% (rounded up)

Step-by-step explanation:

2. I just took the outcome needed and decided by the possible outcomes.

3. That was a compound event so I just got the probability of flipping tails (1/2) and multiplied it by the probability of getting a white ball (1/7)

4. another compound event, I got the probability of getting a medium (1/3) and multiplied it by getting yellow (1/2)

hope this helped!

3 0

3 years ago

The Petrified Forest National Park in Arizona recently expanded their boundaries by 93,533 acres. The original acreage was 125,0

leonid [27]

Answer: The new acreage of the park is 218,533.

Step-by-step explanation:

Since we have given that

Original acreage = 125,000

Expanded boundary by = 93,533 acres

We need to find the new acreage of the park.

so,we will use

$New\ acreage=Original\ acreage+Expanded\\\\New\ acreage=125000+93533\\\\New\ acreage=218,533$

Hence, The new acreage of the park is 218,533.

4 0

3 years ago