<h3>Given</h3>
regular paper costs $3.79 per ream
recycled paper costs $5.49 per ream
$582.44 was spent for 116 reams
<h3>Find</h3>
the numbers of reams of each type that were purchased
<h3>Solution</h3>
Let r and g represent the numbers of reams of regular and recycled ("green") paper, respectively.
... r + g = 116 . . . . . . . . 116 reams were purchased
... 3.79r + 5.49g = 582.44 . . . . this is the total cost of the purchase
Solve the first equation for r and substitute that into the second equation.
... r = 116 - g
... 3.79(116 - g) + 5.49g = 582.44 . . . . . use the expression for r
... 1.70g + 439.64 = 582.44 . . . . . . . . . simplify
... g = (582.44 -439.64)/1.70 = 84 . . . . subtract the constant, divide by 1.70
... r = 116 -84 = 32 . . . . . . . . . . . . . . . . . use the equation for r
32 regular reams and 84 recycled reams were purchased
I did this in my math the other day and the answer is octagon
i think of it as this 'the more angles there are the larger the angles'
i hope i helped
B=1/2
9/16=1/2b(3/4)
Divide both sides by 3/4
1/4=1\2b
Multiply both sides by 2
Answer: Surface area is equal to 200
Volume is equal to 333.33
Step-by-step explanation:
First, let's do surface area.
The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base
The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.
The lateral height is given as 5 cm.
The area of the base is 10(10) = 100.
We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200.
Now for volume.
The volume of a pyramid is equal to 1/3(area of the base)(height).
We already have the area of the base, which is 100.
The height is given as 10 cm.
Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33.
Hope this helps!
Answer:
(x+1)(x-1)(x+3)(x-3)
Step-by-step explanation:
x4-10x^2+9
Group expression so that the coefficients of the x^2 terms add up to +9.
= x^4 -9x^2 - x^2+9
match coefficients in both groups
= x^4 -9x^2 - (x^2-9)
factor each group
= x^2 (x^2-9) - 1(x^2-9)
now factor out the common factor (x^2-9)
= (x^2-1)(x^2-9)
Finally, factor each quadratic factor
= (x+1)(x-1)(x+3)(x-3)
