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gavmur [86]
3 years ago
10

Calculate the time taken by the light to pass through a nucleus of diameter 1.56 10 -16 m. (speed of light is 3 10 8 m/s)

Physics
1 answer:
slega [8]3 years ago
4 0

Answer:

5.2x10^-25

Explanation:

Time=(1.56x 10^-16)÷(3x10^8)

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The acceleration of gravity is a constant equal to _______ meters per second squared.
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How does the media influence our view of beauty and gender roles?
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What is the mass of a truck if it is accelerating at a rate of 5 m/s2 and hits a parked car with a
sineoko [7]

Answer:

<h3>The answer is 2800 kg</h3>

Explanation:

The mass of the truck can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{14000}{5}  \\

We have the final answer as

<h3>2800 kg</h3>

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5 0
3 years ago
Sobre un barco, que se mueve en forma rectilínea, y con velocidad constante de 30 [km/h], se mueve un perro en el mismo sentido
almond37 [142]

Answer:

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

Explanation:

Para determinar la velocidad del perro con respecto al observador sentado desde la playa a través del concepto de velocidad relativa, descrito en la siguiente fórmula:

v_{P/B} = v_{P} - v_{B} (1)

Donde:

v_{P/B} - Velocidad del perro relativo al barco, en kilómetros por hora.

v_{P} - Velocidad del perro con respecto al observador, en kilómetros por hora.

v_{B} - Velocidad del barco con respecto al observador, en kilómetros por hora.

Si sabemos que v_{B} = 30\,\frac{km}{h} y v_{P/B} = 10\,\frac{km}{h}, entonces la velocidad del perro con respecto al observador es:

v_{P} = v_{B} + v_{P/B}

v_{P} = 30\,\frac{km}{h} + 10\,\frac{km}{h}

v_{P} = 40\,\frac{km}{h}

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

6 0
3 years ago
¿Qué trabajo hace una fuerza de 110 N cuando mueve su punto de aplicación 20 mt en su misma dirección? *
lys-0071 [83]

Answer:

W = 2.200 Joules

Explanation:

Datos (data):

  • Fuerza [force] (F) = 110 N
  • Metros [meters] (m) = 20 m
  • Trabajo [work] (W) = ?

Usar la fórmula (use formula):

  • \boxed{\bold{W = F*d}}

Reemplazar (replace):

  • \boxed{\bold{W = 110\ N*20\ m}}

Resolver la multiplicación, recuerda que 1 N * 1 m = 1 J (resolve the multiplication, remember that 1 N * 1 m = 1 J:

  • \boxed{\boxed{\bold{W =2.200\ J}}}

Greetings.

7 0
3 years ago
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