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olga_2 [115]
4 years ago
8

A hydraulic turbine is used to generate power by using the water in a dam. The elevation difference between the free surfaces up

stream and downstream of the dam is 131 m. The water is supplied to the turbine at a rate of 201 kg/s. If the shaft power output from the turbine is 234 kW, the efficiency of the turbine is_________.
Physics
1 answer:
Serjik [45]4 years ago
3 0

Answer:

0.906

Explanation:

Let g = 9.81 m/s2. We can calculate the rate of change in potential energy when m = 201kg of water is falling down a distance of h = 131m per second

\dot{E_p} = \dot{m}gh = 201*9.81*131 = 258307 J/s (W) = 258.307 kW

So the efficiency of the water turbine is the ratio of output power over input power:

\frac{234}{258.307} = 0.906

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Answer:

v2 = 65 m/s

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Given;

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diameter d1 = 3.0 cm

diameter (nozzle) d2 = 0.3 cm

The volumetric flow rates in both the hose and the nozzle are the same.

V1 = V2 ........1

Volumetric flow rate V = cross sectional area × speed of flow

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V = v(πd^2)/4 ....2

Substituting equation 2 to 1;

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Substituting the given values;

v2 = (0.65 × 3^2)/0.3^2

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What chemicals does the body produce to keep neutral pH?
AleksandrR [38]
The body produces Buffers that can neutralize acids
6 0
3 years ago
An object is pulled with a 85 N force inclined at 27° along a horizontal surface ABC
OLEGan [10]

Answer:

m = 15.15 kg

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Newton's Second Law of motion states that when an unbalanced force is applied on a body, an acceleration is produced in it in the direction of force. The component of force along the horizontal direction here, will be given by the Newton's Second Law as:

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