Answer:
a jak to chces vidieť nápis podrobnejsie
Answer:
True
Explanation:
Because <em><u>half</u></em><em><u> </u></em><em><u>life</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>length</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>takes</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>the</u></em><em><u>,</u></em>half of the radioactive atoms of a specific radionuclied to decay.
Answer:
The answer to your question is a = 1.3 m/s²
Explanation:
Centripetal acceleration is the motion of a body that transverse a circular path.
Data
mass = 7 kg
radius = r = 1.3 m
angular rate = w = 1.0 rev/s
centripetal acceleration = a = ?
Formula
a = rw²
Substitution
a = (1.3)(1)²
Simplification and result
a = 1.3 m/s²
Before going to solve this question first we have to understand specific heat capacity of a substance .
The specific heat of a substance is defined as amount of heat required to raise the temperature of 1 gram of substance through one degree Celsius. Let us consider a substance whose mass is m.Let Q amount of heat is given to it as a result of which its temperature is raised from T to T'.
Hence specific heat of a substance is calculated as-
![c= \frac{Q}{m[T'-T]}](https://tex.z-dn.net/?f=c%3D%20%5Cfrac%7BQ%7D%7Bm%5BT%27-T%5D%7D)
Here c is the specific heat capacity.
The substance whose specific heat capacity is more will take more time to be heated up to a certain temperature as compared to a substance having low specific heat which is to be heated up to the same temperature.
As per the question John is experimenting on sand and water.Between sand and water,water has the specific heat 1 cal/gram per degree centigrade which is larger as compared to sand.Hence sand will be heated faster as compared to water.The substance which is heated faster will also cools faster.
From this experiment John concludes that water has more specific heat as compared to sand.
Answer:
The mass rate of the cooling water required is: 
Explanation:
First, write the energy balance for the condensator: The energy that enters to the equipment is the same that goes out from it; consider that there is no heat transfer to the surroundings and kinetic and potential energy changes are despreciable.

Where w refers to the cooling water and s to the steam flow. Reorganizing,

Write the difference of enthalpy for water as Cp (Tout-Tin):

This equation will let us to calculate the mass rate required. Now, let's get the enthalpy and Cp data. The enthalpies can be read from the steam tables (I attach the tables I used). According to that,
and
can be calculated as:
.
The Cp of water at 25ºC (which is the expected average temperature for water) is: 4.176
. If the average temperature is actually different, it won't mean a considerable mistake. Also we know that
, so let's work with the limit case, which is
to calculate the minimum cooling water mass rate required (A higher one will give a lower temperature difference as a result). Finally, replace data:
