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Firlakuza [10]
3 years ago
11

(SHOULDN'T BE HARD!!!!) How does gravity impact two objects in space?

Physics
1 answer:
Elis [28]3 years ago
8 0

Gravity is a very important force. Every object in space exerts a gravitational pull on every other, and so gravity influences the paths taken by everything traveling through space. It is the glue that holds together entire galaxies. It keeps planets in orbit.

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You have a circuit with a 50 Ω , a 100 Ω , and a 150 Ω - resistor connected in series. (a) Rank the current through them from hi
olga2289 [7]

Explanation:

(a) A circuit has 50 Ω, a 100Ω and a 150 Ω resistor are connected in series. We know that in series combination, current through each resistor is same. So, current through a 50 Ω, a 100Ω and a 150 Ω resistor is same.

(b) Ohm's law of given by :

V = I R

V is potential difference. As I is same, so, the resistor having highest resistance will have highest potential difference. So,

V_3>V_2>V_1.

Hence, this is the required solution.

5 0
3 years ago
What is an electromagnetic wave?
satela [25.4K]
I think it is B. Sorry if I’m wrong
6 0
3 years ago
a metal bar 70cm long and 4.00 kg in mass supported on two knief -edge placed 10 cm from each end. a 6.00 kg weight is suspended
Klio2033 [76]
First, you make a diagram of all the forces acting on the system. This is shown in the figure. We have to determine F1 and F4. Let's do a momentum balance. Momentum is conserved so the summation of all momentum is equal to zero. Momentum is force*distance.

To determine F1: (reference is F4, so F4=0)

∑Momentum = 0 = -F2 - F3 + F1
0 = (-4 kg)(9.81 m/s2)(0.25m)-(6kg)(9.81 m/s2)(0.5-0.3m)+F1(0.5-0.1m)
F1 = 53.96 N (left knife-edge)

To determine F4: (reference is F1, so F1=0)

∑Momentum = 0 = -F2 - F3 + F4
0 = (-4 kg)(9.81 m/s2)(0.25m)-(6kg)(9.81 m/s2)(0.5-0.2m)+F4(0.5-0.1m)
F4 = 68.67 N (right knife-edge) 


4 0
3 years ago
Read 2 more answers
If you accelerate from rest at 12m/s^2 for 5 seconds, what is your finally velocity?
jeka94

Answer:

v=60m/s

Explanation:

Use the Kinematic Equation:

v=v_o+at

Plug in what is given and solve

v=0+(12)(5)

v=60m/s

3 0
2 years ago
A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the high
m_a_m_a [10]

Answer:

factor that bug maximum KE change is 0.52284

Explanation:

given data

vertical distance = 6.5 cm

ripples decrease to =  4.7 cm

solution

We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

KE = (0.5) × m × A² × ω²     .................1

and kinetic energy is  directly proportional to square of the amplitude.

so

\frac{KE2}{KE1} =  \frac{A2^2}{A1^2}      .............2

\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}

\frac{KE2}{KE1} = 0.52284

so factor that bug maximum KE change is 0.52284

5 0
4 years ago
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