Answer:
0
Step-by-step explanation:
Given that,
6m - 2n=0
=>6m=2n
=>n=3m [divide both side by 2]
& mn=12
Now,
216c - 8n³
= 216m³- 8(3m)³
=216m³- 8 .27m³
=216m³- 216m³
=0
Answer:
Step-by-step explanation:
Days with t are: Tuesday, Thursday and Saturday.
In the period of time given there are 20 T days (20 x 3 = 60 oranges)
In the period of time given there are ? no T days (27 x 2 = 54 oranges)
60 + 54 = 114 Oranges eaten over the school holidays
The correct answer is: [D]: "5 (five)" .
______________________________________________________
<u>Note</u>: The term of "degree 8" is the term with a variable with
an exponent of "8" ; which in this case is " + 5x⁸ ".
The "coefficient" is "5" (five).
______________________________________________________
Answer:
μ = 235.38
σ = 234.54
Step-by-step explanation:
Assuming the table is as follows:
![\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DSavings%26Frequency%5C%5C%5C%240-%5C%24199%26339%5C%5C%5C%24200-%5C%24399%2686%5C%5C%5C%24400-%5C%24599%2655%5C%5C%5C%24600-%5C%24799%2618%5C%5C%5C%24800-%5C%24999%2611%5C%5C%5C%241000-%5C%241199%268%5C%5C%5C%241200-%5C%241399%263%5Cend%7Barray%7D%5Cright%5D)
This is an example of grouped data, where a range of values is given rather than a single data point. First, find the total frequency.
n = 339 + 86 + 55 + 18 + 11 + 8 + 3
n = 520
The mean is the expected value using the midpoints of each range.
μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520
μ = 122400 / 520
μ = 235.38
The variance is:
σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)
σ² = 55009.7
The standard deviation is:
σ = 234.54
Answer: y = 1/4x - 4
Step-by-step explanation: write it in slope intercept form y = mx + b
