3 years ago

Please help a) B) C)

Mathematics

1 answer:

fomenos3 years ago

6 0

I'm pretty sure it should be B)

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(x-1)^2+(2-x)^2-3(x-5)*(x-5)

Natali5045456 [20]

Answer:

$-x^2+24x-70$

Step-by-step explanation:

$(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5 - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70$

Formula used =

$(a-b)^2 = a^2+ 2ab + b^2$

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kotegsom [21]

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2 years ago

Read 2 more answers

‼️please help ASAP.

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Try to do them on math -way

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2 years ago

If u can help with this question, the options for both x' s are -8,-7,-6,-5,-4,-3,-2,-1,1,2,3,4,5,6,7,8

Simora [160]

1x + 1y = 100....multiply by -3/8
3/8x + 7/8y = 2000

no need to multiply the other equation by anything....the x's will cancel because one will be -3/8x and one will be 3/8x

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