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guapka [62]
3 years ago
10

tess was mowing lawns for a week and earned a profit of $48. She charged her customers $10 per hour, and she paid $32 for gas fo

r the lawn mover.
Mathematics
1 answer:
yawa3891 [41]3 years ago
4 0

Answer:

Assuming you need to find how many hours she worked the answer is 8.

Step-by-step explanation:

Before she bought gas she had a total of $80 (48+32). Divide this by 10 and you will get how many hours she worked. I am assuming that was the question.

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Choice d) can be represented by a discrete probability distribution, the other choices cannot be so represented.
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2 years ago
I need help with this please.
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Answer:

the slope is 60

Step-by-step explanation:

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Only answer this if you have an explanation and if you know what the answer is.
Rzqust [24]

Answer:

B. 3

Step-by-step explanation:

You can use online calculators for this like symbolab.com for steps! Here is your specific question answered with steps: https://www.symbolab.com/solver/step-by-step/%206%20%E2%88%92%203%5E%7B3%7D%20%5Cdiv%5Cleft(2%5E%7B2%7D%20%2B%205%5Cright)%20

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miss Akunina [59]

Answer:

Probability that she selects a blue bead

= 3/9

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Step-by-step explanation:

Please mark me brainliest

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
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