Answer: the standard hourly pay is $3.05
Step-by-step explanation:
Let x represent the standard hourly pay that he gets for the first 40 hours.
Therefore, the total amount that he gets for the first 40 hours of work in a given week is 40x.
At Dairy Queen, he earned double time for any hours worked over 40 in a given week. This means that the hourly rate is 2x
If during one week, he worked 51 hours, it means that the overtime is 51 - 40 = 11 hours
Total amount earned for overtime is
11 × 2x = 22x
If the total amount that he earned for the week is $189.10, then
40x + 22x = 189.1
62x = 189.1
x = 189.1/62 = 3.05
The statement that represents the given binomial above is option 2. Both points are positive if and only if they are in the first quadrant. It is true that the coordinate point is in the first quadrant, and both points are positive and it's true that both points are positive if the coordinate point is in the first quadrant. Hope this answer helps.
Answer:
A. 6
Step-by-step explanation:
f(x) = x² − 12x + 7
To complete the square, we first factor the leading coefficient to make it 1 (which it already is).
Then, we take half the second coefficient, square it, and then add to both sides. So (-12/2)² = (-6)² = 36.
f(x) + 36 = x² − 12x + 36 + 7
Then we factor the perfect square:
f(x) + 36 = (x − 6)² + 7
Then solve for f(x) by subtracting and simplifying:
f(x) = (x − 6)² + 7 − 36
f(x) = (x − 6)² − 29
So the value of a is 6.
You have to do 43 times 8 which is 344 students :)
Let "c" and "q" represent the numbers of bottles of Classic and Quantum that should be produced each day to maximize profit. The problem conditions give rise to 3 inequalities:
.. 0.500c +0.550q ≤ 100 . . . . . . . liters of water
.. 0.600c +0.200q ≤ 100 . . . . . . . kg of sugar
.. 0.1c +0.2q ≤ 32 . . . . . . . . . . . . . grams of caramel
These can be plotted on a graph to find the feasible region where c and q satisfy all constraints. You find that the caramel constraint does not come into play. The graph below has c plotted on the horizontal axis and q plotted on the vertical axis.
Optimum production occurs near c = 152.17 and q = 43.48. Examination of profit figures for solutions near those values reveals the best result for (c, q) = (153, 41). Those levels of production give a profit of 6899p per day.
To maximize profit, Cartesian Cola should produce each day
.. 153 bottles of Classic
.. 41 bottles of Quantum per day.
Profit will be 6899p per day.
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The problem statement gives no clue as to the currency equivalent of 100p.