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3 years ago

Suppose a group of dancers performed the Round Dance at an Indigenous Peoples' Day

Mathematics

2 answers:

elixir [45]3 years ago

8 0

The diameter of the circle is above me theyre right (have to spam bcs im on mobile) OAHSOEJWOEHOWHEOEBDKDBF

love history [14]3 years ago

3 0

Answer:

4.27 meters

Step-by-step explanation:

You might be interested in

For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th

alexira [117]

Answer:

The inner function is $h(x)=4x^2 + 8$ and the outer function is $g(x)=3x^5$ .

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

Step-by-step explanation:

A composite function can be written as $g(h(x))$ , where $h$ and $g$ are basic functions.

For the function $f(x)=3(4x^2+8)^5$ .

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have $4x^2+8$ inside parentheses. So $h(x)=4x^2 + 8$ is the inner function and the outer function is $g(x)=3x^5$ .

The chain rule says:

$\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

It tells us how to differentiate composite functions.

The function $f(x)=3(4x^2+8)^5$ is the composition, $g(h(x))$ , of

outside function: $g(x)=3x^5$

inside function: $h(x)=4x^2 + 8$

The derivative of this is computed as

$\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4$

The derivative of the function is $\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4$ .

3 0

3 years ago

Select the correct answer from each drop-down menu.

vazorg [7]

Answer:

Step 1: Distribute $-2$ to $5x$ and $8$

Step 2: Subtract from both sides of the equation $6x$

Step 3: Add to both sides of the equation $16$

Step 4: Divide both sides of the equation by $-16$

Step-by-step explanation:

Step 1: Apply the Distributive Property. Then you must distribute $-2$ to $5x$ and $8$

Then:

$-2(5x+8)=14+6x\\\\-10x-16=14+6x$

Step 2: You must apply the Subtraction property of Equality and subtract $6x$ from both sides of the equation. Then:

$-10x-16-6x=14+6x-6x\\\\-16x-16=14$

Step 3: You must apply the Addition property of Equality and add $16$ to both sides of the equation. Then:

$-16x-16+16=14+16\\\\-16x=30$

Step 4: You must apply the Division property of Equality and divide both sides by $-16$ . Then:

$\frac{-16x}{-16}=\frac{30}{-16}\\\\x=\frac{30}{-16}\\\\x=-\frac{15}{8}$

6 0

3 years ago

What is 3 1/2 - 2 5/7 and show the work

Hunter-Best [27]

$3 \frac{1}{2} -2 \frac{5}{7} = \frac{(3\cdot2)+1}{2} - \frac{(2\cdot7)+5}{7} = \frac{7}{2} - \frac{19}{7} \\\\= \frac{7\times 7}{2\times 7} - \frac{19\times 2}{7\times 2} = \frac{49}{14} - \frac{38}{14} \\\\= \frac{49-38}{14} =\boxed{\bf{\frac{11}{14}}}$

6 0

4 years ago

Let Upper C left-parenthesis q right-parenthesis represent the cost, Upper R left-parenthesis q right-parenthesis the revenue, a

Dennis_Churaev [7]

Answer:

(a)$13

(b) Loss of $4

Step-by-step explanation:

C(q) represents Cost of producing q units.

R(q) represents Revenue generated from q units.

P(q) represents Total Profit made from producing q units.

Marginal analysis is concerned with estimating the effect on quantities such as cost, revenue, and profit when the level of production is changed by a unit amount. For example, if C(q) is the cost of producing q units of a certain commodity, then the marginal cost, MC(q), is the additional cost of producing one more unit and is given by the difference

MC(q) = C(q + 1) − C(q).

Using the estimation

C'(q)≈ $\frac{C(q+1)-C(q)}{(q+1)-q}$ =C(q+1)-C(q)

We find out that MC(q)=C'(q)

We can therefore compute the marginal cost by the derivative C'(q).

This also holds for Revenue, R(q) and Profit, P(q).

(a) If C'(50)=75 and R'(50)=88

51st item.

P'(50)=R'(50)-C'(50)

=88-75=$13

The profit earned from the 51st item will be approximately $13.

(b) If C'(90)=71 and R'(90)=67, approximately how much profit is earned by the 91st item.

P'(90)=R'(90)-C'(90)

=67-71= -$4

The profit earned from the 91 st item will be approximately -$4.

There was a loss of $4.

4 0

3 years ago

Let f = (ax + by + 4z) i + (x + cz) j + (9y + mx) k where a, b,c, and m are constants.

Tom [10]

Let $\mathcal R$ be an arbitrary closed region with boundary the surface $\mathcal S$ . By the divergence theorem,

$\displaysytle\iint_{\mathcal S}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

We have

$\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial(ax+by+4z)}{\partial x}+\dfrac{\partial(x+cz)}{\partial y}+\dfrac{\partial(9y+mx)}{\partial z}=a$

so that the flux satisfies

$\displaystyle a\iiint_{\mathcal R}\mathrm dV=0$

We're assuming $\mathcal R$ is a closed region, and the integral above is its volume, which must be positive. This means we must have $a=0$ .

7 0

3 years ago