Let the larger number be w and the smaller number be k;
5w-11=3k
3k+16=4w
Reorganizing the equations;
5w-3k=11
4w-3k=16
Subtracting equation 2 from equation 1:
w=-5
Replacing value of w in equation 1;
5(-5)-11=3k
-25-11=3k
3k=-36
k=-12
The numbers are -5 and -12
278 divided by 59 is 4.712, which can be rounded to 5
the answer is d. 5
Hello! And thank you for your question!
Use Pemdas to get
3^(n+2)*4=3^28
Rewrite the equation:
3^4(n+2) = 3^28
Cancel the base of 3:
4(n + 2) = 28
Then divide 4 on both sides:
2 + n = 28/4
Simplify 28/4:
2 + n = 7
Subtract 2 on both sides:
n = 7 - 2
Finally simplify 7 - 2:
n = 5
Final Answer:
n = 5
