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True [87]
3 years ago
5

You entered a contest through your local television station. There is one first prize of a new car! There are 5 second place pri

zes of $1000, and 20 third place prizes of $100. If there are 2000 entries, what is the chance that you will win one of the 2nd place prizes?
Mathematics
2 answers:
Grace [21]3 years ago
8 0

Answer:

\frac{1}{400} or 0.0025 0r 0.25%

Step-by-step explanation:

There are three categories that will get a prize

1) First place = 1 person

2) Second place = 5 persons

3) Third place = 20 persons

A total of 26 people will get prizes.

However, we want to determine your chance to win one of the second place prizes

There are 5 prizes in second place

This means out of a total of 2000 people, you could be among the 5

i.e 5 out of 2000

This is \frac{5}{2000} = \frac{1}{400} = 0.0025

This means you have a chance of 1 out of 400

= 0.25%

Helga [31]3 years ago
8 0
There are 26 people who will get the chance to get first, second, or third place. But, you need to focus on the 5 second place prizes. The chance that you will win a second place prize is 5 to 2000, or, simplified, is a 1 to 400 chance. In a percent, that would be a 0.25% chance that you will win one of the second place prizes. Hope I helped :)
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3 years ago
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miskamm [114]

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<em><u>Explanation</u></em>

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<u>The formula for Mean deviation</u> = \sum \frac{|x_{i}- \mu|}{N} , where x_{i} is the given data from i=1 to i=10 , \mu is the mean of the data and N is the total number of data. So.....

|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1

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3 years ago
Please help me quickly.<br> Thank you
Ludmilka [50]
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Hope it helps : )
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2 years ago
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