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Slav-nsk [51]
4 years ago
14

In the equation y=x2 , which of the following explains the unit rate?

Mathematics
1 answer:
muminat4 years ago
3 0
The only logical answer is, 2 because the unit rate is value of y when x=1.

y=(1)2
y=2.

As I stated in the same question, the "Unit Rate" is not hard, it's just slope. They are trying to trick you by saying "unit rate". Your unit rate is x2.
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Identify the type of hypothesis test below. H0:X=10.2, Ha:X>10.2 Select the correct answer below: The hypothesis test is two-
Ganezh [65]

Answer:

The hypothesis test is right-tailed

Step-by-step explanation:

To identify a one tailed test, the claim in the case study tests for the either of the two options of greater or less than the mean value in the null hypothesis.

While for a two tailed test, the claim always test for both options: greater and less than the mean value.

Thus given this: H0:X=10.2, Ha:X>10.2, there is only the option of > in the alternative claim thus it is a one tailed hypothesis test and right tailed.

A test with the greater than option is right tailed while that with the less than option is left tailed.

4 0
3 years ago
A system of two linear inequalities is graphed as shown, where the solution region is shaded.
Zinaida [17]

Answer:

(-3,2) is located in the solution region.

Step-by-step explanation:

3 0
3 years ago
El que responda bien 5 estrellas y un gracias 7u7
adoni [48]

Answer: AB=12

Los triangulos BCD y ADE son iguales por tener dos lados y el angulo comprendido respectivamente iguales. por tanto AE=DC=4

Luego AB = AE+EB = 4+8 = 12

5 0
3 years ago
I NEED HELP ASAP!!!! PLEASE ANSWER
dmitriy555 [2]

2nd ones your answer


6 0
3 years ago
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All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,
Anika [276]

Answer:

Step-by-step explanation:

If you have a square of side l, its diagonal would be l\sqrt{2}, and its area l^2

If the big square has a area of 900, this implies that its side is \sqrt{900}, so the two diagonal of squares 2 and 4 added together would be \sqrt{900}, therefore one diagonal wold be \frac{\sqrt{900}}{2}. and its side \frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}. The area (of one square) is (\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}

finally the two areas combined (squares 2 and 4) would be 225

6 0
3 years ago
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