1) -2(n-6)
-2n+12
2) (5b-4)1/5
(5b-4)(1/5)
(5b)(1/5)+(-4)(1/5)
b+-4/5
3) 2/3(6y+9)
(2/3)(6y)+(2/3)(9)
4y+6
4) 4t-7t
-3t
5) -18v^2+23v^2
5v^2
6) 13q-30q
-17q
Answer:
Approximately 313 cakes of similar size as those 50 cut from the smaller cake, can be cut from the bigger cake.
Step-by-step explanation:
The complete question is with the missing image of the cakes is attached to this solution.
From the image provided, the dimensions of the smaller cake = 2 ft × 1.6 ft
The dimensions of the larger cake = 5 ft × 4 ft
50 cakes are obtained from the smaller cake, how many cakes can be obtained from the bigger cake?
Area of the smaller cake = 2 × 1.6 = 3.2 ft²
Area of the bigger cake = 5 × 4 = 20 ft²
3.2 ft² cake provides 50 cakes.
20 ft² cake will provide (20×50/3.2) cakes = 312.5 cakes
Rounded to the nearest piece of cake = 313 cakes
Hope this Helps!!!
Top 2nd one isn’t a function
Answer:

Step-by-step explanation:
Rewrite the equation using the next propierties:

Cancel logarithms by taking exp of both sides:

Multiplying both sides by -x and factoring:

Factoring:

The solutions are:

Evaluating x=-4

This is an absurd because ln(x) is undefined for 
Evaluating x=-1

Which is correct, hence the solution is:

Answer: $25
Step-by-step explanation:
2500/100 = 25